c语言实现谷歌笔试题：返回参数二进制中1的个数

#include <stdio.h>

int count_one_bits(int num)
{
int count = 0;
while(num)
{
count++;
num = num&(num-1);
}
return count;
}

int main()
{
int num = -1;
printf("count = %d\n", count_one_bits(num));

return 0;
}