322. Coin Change
2016-09-13 14:45
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动态规划里例题,硬币问题。
p[i] = dp[i - coin[j]] + 1;
注意i < coin[j] dp[i-coin[j]]无解都要跳过。
第一次看到动态规划觉得好神奇。。
p[i] = dp[i - coin[j]] + 1;
注意i < coin[j] dp[i-coin[j]]无解都要跳过。
public class Solution { public int coinChange(int[] coins, int amount) { int[] dp = new int[amount+1]; Arrays.fill(dp,Integer.MAX_VALUE); //dp[i] = dp[i - coin[j]] + 1; dp[0] = 0; for(int i = 0; i <= amount; i++) { for(int j = 0; j < coins.length;j++) { if(i < coins[j] || dp[i-coins[j]] == Integer.MAX_VALUE) continue; dp[i] = Math.min(dp[i],dp[i - coins[j]]+1); } } if(dp[amount] == Integer.MAX_VALUE) return -1; else return dp[amount]; } }
第一次看到动态规划觉得好神奇。。
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