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python核心编程学习笔记-2016-08-28-01-习题18-4和习题18-9

2016-08-28 14:39 1291 查看
        习题18-4

#-*-coding: utf-8-*-

import threading
import time

char = chr(input("Enter a positive number from 0 to 255: "))
filename = raw_input("Enter a filename: ")

print "*** Single Thread"
count = 0
time_start = time.clock()
with open(filename, 'r') as f:
for eachLine in f:
if eachLine == bin(ord(char)) + '\n':
count += 1
f.close()
time_end = time.clock()
print "%s occur %d time in %s." % (char, count, filename)
print "using", (time_end - time_start), 's'

print "*** Multiple Threads"

counts = []
threadNum = int(raw_input("Enter the number of threads: "))
def read(char, text):
count = 0
for eachLine in text:
if eachLine == bin(ord(char)) + '\n':
count += 1
counts.append(count)

time_start = time.clock()
with open(filename, 'r') as f:
text = f.readlines()
lines = len(text) / threadNum
threads = []
for i in range(threadNum):
if (i + 1) * (len(text) / threadNum) <= len(text):
t = threading.Thread(target=read, args=(char, text[(i * lines):((i + 1) * lines)])) # 将文件分块,不同线程分别读取。
else:
t = threading.Thread(target=read, args=(char, text[(i * lines):]))
threads.append(t)
threads[i].start()

for i in range(threadNum):
threads[i].join()
f.close()
count = sum(counts)
time_end = time.clock()
print "%s occur %d time in %s." % (char, count, filename)
print "using", (time_end - time_start), 's'

         但是看结果



        习题18-9

#-*-coding: utf-8-*-

import threading
import time

filenames = ['ex9-19.txt', 'ex9-19.txt', 'ex9-19.txt', 'ex9-19.txt', 'ex9-19.txt']
sin_counts = []
mul_counts = []
def countline(filename, counts):
f = open(filename, 'r')
count = 0
for eachLine in f:
count += 1
counts.append(count)

print "*** Single thread"
time_start = time.clock()
for i in range(len(filenames)):
countline(filenames[i], sin_counts)
time_end = time.clock()
print sin_counts
print time_end - time_start

print "*** Multiply threads"
time_start = time.clock()
threads = []
for i in range(len(filenames)):
t = threading.Thread(target=countline, args=(filenames[i], mul_counts))
threads.append(t)

for i in range(len(filenames)):
threads[i].start()

for i in range(len(filenames)):
threads[i].join()

time_end = time.clock()
print mul_counts
print time_end - time_start
        结果



        单线程比多线程还要快。这个可能是由于这两个程序都是计算密集型的原因吧。具体原因暂时存疑吧,等到具备操作系统的基本知识后,或许就会明白了。
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