Implement Stack using Queues
2016-08-25 15:38
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题目:
Implement the following operations of a stack using queues.
push(x) -- Push element x onto stack.
pop() -- Removes the element on top of the stack.
top() -- Get the top element.
empty() -- Return whether the stack is empty.
Notes:
You must use only standard operations of a queue -- which means only
Depending on your language, queue may not be supported natively. You may simulate a queue by using a list or deque (double-ended queue), as long as you use only standard operations of a queue.
You may assume that all operations are valid (for example, no pop or top operations will be called on an empty stack).
Update (2015-06-11):
The class name of the Java function had been updated to
MyStack instead of Stack.
分析:
只有push,需要一次移动,其他都一样
代码:
class Stack {
public:
queue<int> q;
// Push element x onto stack.
void push(int x) {
q.push(x);
for(int i=1; i<q.size(); i++)
{
q.push(q.front());
q.pop();
}
}
// Removes the element on top of the stack.
void pop() {
q.pop();
}
// Get the top element.
int top() {
return q.front();
}
// Return whether the stack is empty.
bool empty() {
return q.empty();
}
};
Implement the following operations of a stack using queues.
push(x) -- Push element x onto stack.
pop() -- Removes the element on top of the stack.
top() -- Get the top element.
empty() -- Return whether the stack is empty.
Notes:
You must use only standard operations of a queue -- which means only
push to back,
peek/pop from front,
size, and
is emptyoperations are valid.
Depending on your language, queue may not be supported natively. You may simulate a queue by using a list or deque (double-ended queue), as long as you use only standard operations of a queue.
You may assume that all operations are valid (for example, no pop or top operations will be called on an empty stack).
Update (2015-06-11):
The class name of the Java function had been updated to
MyStack instead of Stack.
分析:
只有push,需要一次移动,其他都一样
代码:
class Stack {
public:
queue<int> q;
// Push element x onto stack.
void push(int x) {
q.push(x);
for(int i=1; i<q.size(); i++)
{
q.push(q.front());
q.pop();
}
}
// Removes the element on top of the stack.
void pop() {
q.pop();
}
// Get the top element.
int top() {
return q.front();
}
// Return whether the stack is empty.
bool empty() {
return q.empty();
}
};
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