解决jsp下载文件，迅雷下载路径不显示文件名称的问题

如果浏览器安装了迅雷的插件，在jsp页面调用java后台实现文件下载功能时，会自动弹出迅雷下载，迅雷的下载路径会显示.do或者.xhtml之类的，为了解决这个问题，jsp页面修改如下：

写一个<a>标签在页面上：

<a id="downloadUrl" target="_blank"></a>

导出按钮如下：

<a href="javascript:void(0)" id="biz_exp_button" class="easyui-linkbutton"
data-options="iconCls : 'icon-download',plain:true" onclick="javascript:DataMonitor.file_download('wbj');">导出</a>

js代码如下：

var DataMonitor = {
file_download : function(param)
{
url = CONTEXT_PATH + "/sjjk/file_download/";
var $a = $("#downloadUrl");
if(param == 'wbj'){
url += encodeURI("委办局接入数据") + ".xls";
$a.attr("href", url)[0].click();
}else if(param == 'csjcj'){
url += encodeURI("城市级基础库数据") + ".xls";
$a.attr("href", url)[0].click();
}else {

}
$a.attr("href", null);
}
};

java代码如下：

@RequestMapping("file_download/{fileName}.xls")
public void fileDownload(@PathVariable String fileName,
HttpServletResponse response, HttpServletRequest request)
throws Exception {
// String type = request.getParameter("type");
String type = null;
String filename = "";
if (null != fileName) {
filename = fileName.concat(".xls");
if ("委办局接入数据".equals(fileName)) {
type = "wbj";
} else if ("城市级基础库数据".equals(fileName)) {
type = "csjcj";
}
}
if (null == type) {
response.sendError(HttpServletResponse.SC_NOT_FOUND);
return;
}
String userAgent = request.getHeader("User-Agent");
if (userAgent.contains("MSIE") || userAgent.contains("Trident")
|| userAgent.contains("Edge")) {
filename = java.net.URLEncoder.encode(filename, "UTF-8");
} else {
// 非IE浏览器的处理：
filename = new String(filename.getBytes("UTF-8"), "ISO-8859-1");
}
String realPath = request.getSession().getServletContext()
.getRealPath("");
String filePath = this.dataMonitorService
.queryDataToExp(type, realPath);//生成xls文件，返回路径，根据自己的业务修改
File file = new File(filePath);
response.setContentType("application/octet-stream");
response.setHeader("Content-Disposition", "attachment;fileName="
+ filename);
response.setContentLength((int) file.length());
ServletOutputStream out;
try {
FileInputStream inputStream = new FileInputStream(file);
out = response.getOutputStream();
int b = 0;
byte[] buffer = new byte[512];
while (b != -1) {
b = inputStream.read(buffer);
out.write(buffer, 0, b);
}
inputStream.close();
out.close();
out.flush();
} catch (Exception e) {
e.printStackTrace();
}
}