leetCode 58. Length of Last Word 字符串

58. Length of Last Word

Given a string s consists of upper/lower-case alphabets and empty space characters

' '

, return the length of last word in the string.If the last word does not exist, return 0.Note: A word is defined as a character sequence consists of non-space characters only.For example,
Given s =

"Hello World"

,
return

5

.

class Solution {
public:
vector<string> stringSplit(string s, const char * split)
{
vector<string> result;
const int sLen = s.length();
char *cs = new char[sLen + 1];
strcpy(cs, s.data());
char *p;

p = strtok(cs, split);
while (p)
{
printf("%s\n", p);
string tmp(p);
result.push_back(tmp);
p = strtok(NULL, split);
}
return result;
}
int lengthOfLastWord(string s) {
if(s.size() == 0)
return 0;
vector<string> words = stringSplit(s," ");
if(words.size() == 0)
return 0;
return words[words.size() - 1].size();
}
};

2016-08-10 18:11:30