[LeetCode] Reverse Vowels of a String Python 题解
2016-08-10 06:23
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Reverse Vowels of a String
"""
Write a function that takes a string as input and reverse only the vowels of a string.
Example 1:
Given s = "hello", return "holle".
Example 2:
Given s = "leetcode", return "leotcede".
"""
class Solution(object):
def reverseVowels(self, s):
"""
:type s: str
:rtype: str
"""
ll = list(s)
i = 0
j = len(s) - 1
vl = ['a','e','i', 'o','u', 'A','E','I','O','U']
while i < j:
if ll[i] in vl and ll[j] in vl:
ll[i], ll[j] = ll[j], ll[i]
j = j - 1
i = i + 1
elif ll[i] in vl:
j = j - 1
else:
i = i + 1
return ''.join(ll)
s = Solution()
print s.reverseVowels("leetcode")
"""
Write a function that takes a string as input and reverse only the vowels of a string.
Example 1:
Given s = "hello", return "holle".
Example 2:
Given s = "leetcode", return "leotcede".
"""
class Solution(object):
def reverseVowels(self, s):
"""
:type s: str
:rtype: str
"""
ll = list(s)
i = 0
j = len(s) - 1
vl = ['a','e','i', 'o','u', 'A','E','I','O','U']
while i < j:
if ll[i] in vl and ll[j] in vl:
ll[i], ll[j] = ll[j], ll[i]
j = j - 1
i = i + 1
elif ll[i] in vl:
j = j - 1
else:
i = i + 1
return ''.join(ll)
s = Solution()
print s.reverseVowels("leetcode")
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