2016 北邮暑期训练3-C题（CodeForces 699B One Bomb）白痴题

Description

You are given a description of a depot. It is a rectangular checkered field of n × m size. Each cell in a field can be empty (“.”) or it can be occupied by a wall (“*”).

You have one bomb. If you lay the bomb at the cell (x, y), then after triggering it will wipe out all walls in the row x and all walls in the column y.

You are to determine if it is possible to wipe out all walls in the depot by placing and triggering exactly one bomb. The bomb can be laid both in an empty cell or in a cell occupied by a wall.

Input

The first line contains two positive integers n and m (1 ≤ n, m ≤ 1000) — the number of rows and columns in the depot field.

The next n lines contain m symbols “.” and “” each — the description of the field. j-th symbol in i-th of them stands for cell (i, j). If the symbol is equal to “.”, then the corresponding cell is empty, otherwise it equals “” and the corresponding cell is occupied by a wall.

Output

If it is impossible to wipe out all walls by placing and triggering exactly one bomb, then print “NO” in the first line (without quotes).

Otherwise print “YES” (without quotes) in the first line and two integers in the second line — the coordinates of the cell at which the bomb should be laid. If there are multiple answers, print any of them.

Sample Input

Input

3 4

.*..

….

.*..

Output

YES

1 2

Input

3 3

..*

.*.

*..

Output

NO

Input

6 5

..*..

..*..

..*..

..*..

..*..

Output

YES

3 3

题目大意：

输入一个矩阵，其中*表示墙，.表示路，有一个炸弹，引爆时能炸掉所在行和列的墙，问能不能放置一个炸弹炸毁所有的墙？如果能，输出坐标。

题目分析：

用两个数组分别记录每一行和每一列的墙数，然后暴力枚举每一个点就行了。在LC里这也就是easy难度。

ac代码：

#include <iostream>
#include <cstdio>
using namespace std;
int main() {
int m,n;
char cell[1005][1005];
int row[1005],col[1005];
int wall=0;
scanf("%d %d",&n,&m);
for(int i=0;i<n;i++) {
scanf("%s",cell[i]);
row[i]=0;
for(int j=0;j<m;j++)
if(cell[i][j]=='*') {
row[i]++;
wall++;
}
}
for(int j=0;j<m;j++) {
col[j]=0;
for(int i=0;i<n;i++) {
if(cell[i][j]=='*')
col[j]++;
}
}
for(int i=0;i<n;i++) {
for(int j=0;j<m;j++) {
int bombs=row[i]+col[j];
if(cell[i][j]=='*')
bombs--;
if(bombs==wall) {
printf("YES\n%d %d\n",i+1,j+1);
return 0;
}
}
}
printf("NO\n");
}