python模拟登录qq邮箱

     前两天做一个任务，要写一个收取qq邮箱邮件的脚本。开始认为挺简单，后来发现还是有一些坑在里面。

    首先使用python尝试模拟登录qq邮箱，发现普通用户已经不能通过账号密码模拟登录qq邮箱了。要用到授权码。（具体查看qq邮箱账号设置） 首先打开qq邮箱生成授权码，然后模拟登录中使用此授权码登录。

接收服务器：

pop.exmail.qq.com(使用SSL，端口号995)

发送服务器：

smtp.exmail.qq.com(使用SSL，端口号465)

这是企业邮箱。个人邮箱的话服务器地址没有exmail，并且个人邮箱需要用到授权码。

#!/usr/bin/python
# -*- coding:utf-8 -*-

import poplib, pprint, email, sys, time, email, time, smtplib, imaplib
from datetime import datetime, timedelta, date
from email.mime.text import MIMEText
from email.header import Header
#设置命令窗口输出使用UTF-8编码
reload(sys)
sys.setdefaultencoding( "utf-8" )

# 第三方 SMTP 服务 注意这是企业邮箱 如果是个人邮箱，密码要用授权码，服务器地址没有exmail
mail_smtp_host= "smtp.exmail.qq.com" # 设置smtp服务器
mail_pop_host= "pop.exmail.qq.com" # 设置pop服务器
mail_user= "" # 用户名
mail_pass= "" # 口令,QQ邮箱是输入授权码，在qq邮箱设置 里用验证过的手机发送短信获得，不含空格

'''
/*DISCRIPTION
* Decoding charsert
* ARGUMENTS
* string need be Decodinged
* RETURN
* NOTES
*/
'''
def Decoding(str):
if(str[0][1] == None): return unicode(str[0][0], 'gb18030')
else: return unicode(str[0][0], str[0][1])

'''
/*DISCRIPTION
* Send the mail to the unsubmit
* ARGUMENTS
* string need be Decodinged
* RETURN
* NOTES
*/
'''
def SendEmail():
sender = ''
receivers = [''] # 接收邮件，可设置为你的QQ邮箱或者其他邮箱

message = MIMEText('a test for python', 'plain', 'utf-8')
message['From'] = Header("ppyy", 'utf-8')
message['To'] = Header("you", 'utf-8')

subject = 'my test'
message['Subject'] = Header(subject, 'utf-8')
try:
smtpObj = smtplib.SMTP_SSL(mail_smtp_host, 465)
smtpObj.login(mail_user,mail_pass)
smtpObj.sendmail(sender, receivers, message.as_string())
smtpObj.quit()
print u"邮件发送成功"
except smtplib.SMTPException,e:
print e

def GetEmail():
try:
pp = poplib.POP3_SSL(mail_pop_host)
pp.user(mail_user)
pp.pass_(mail_pass)
ret =pp.stat()
print u"登录成功"
except:
print "can't connect to mailserver"

#遍历邮件的标题
# emailMsgNum, emailSize = pp.stat()
# for i in xrange(1, emailMsgNum+1):
# ret = pp.retr(i)
# mail = email.message_from_string("\n".join(ret[1]))
# subject = email.Header.decode_header(mail['subject'])
# MailSubject = Decoding(subject)
# print MailSubject

ret = pp.retr(2)
msg = email.message_from_string("\n".join(ret[1]))
print msg.get_payload()

# down = pp.retr(1)
# print 'lines:', len(down)
# for line in down[1]:
# print line

pp.quit()
GetEmail();