1100. Mars Numbers (20)-PAT甲级真题

1100.
Mars Numbers (20)

People
on Mars count their numbers with base 13:

Zero
on Earth is called “tret” on Mars.

The
numbers 1 to 12 on Earch is called “jan, feb, mar, apr, may, jun, jly, aug, sep, oct, nov, dec” on Mars, respectively.

For
the next higher digit, Mars people name the 12 numbers as “tam, hel, maa, huh, tou, kes, hei, elo, syy, lok, mer, jou”, respectively.

For
examples, the number 29 on Earth is called “hel mar” on Mars; and “elo nov” on Mars corresponds to 115 on Earth. In order to help communication between people from these two planets, you are supposed to write a program for mutual translation between Earth
and Mars number systems.

Input
Specification:

Each
input file contains one test case. For each case, the first line contains a positive integer N (< 100). Then N lines follow, each contains a number in [0, 169), given either in the form of an Earth number, or that of Mars.

Output
Specification:

For
each number, print in a line the corresponding number in the other language.

Sample
Input:

4

29

5

elo
nov

tam

Sample
Output:

hel
mar

may

115

13

#include <iostream>
#include <string>
#include <cctype>
using namespace std;
string a[13] = {"tret", "jan", "feb", "mar", "apr", "may", "jun", "jly", "aug", "sep", "oct",
"nov", "dec"};
string b[13] = {"", "tam", "hel", "maa", "huh", "tou", "kes", "hei", "elo", "syy",
"lok", "mer", "jou"};
void func1(string s) {
int len = s.length();
int num = 0;
for (int i = 0; i < len; i++) {
num = num * 10 + (s[i] - '0');
}
cout << b[num / 13];
if((num % 13) && (num / 13)) {
cout << " " << a[num % 13];
} else if(num % 13) {
cout << a[num % 13];
} else if(num == 0) {
cout << a[num % 13];
}
}

void func2(string s) {
int len = s.length();
int num = 0;
if(len == 4) {
cout << 0;
return ;
} else if (len == 3) {
for (int i = 1; i <= 12; i++) {
if (s == a[i]) {
cout << i;
return ;
}
if (s == b[i]) {
cout << i * 13;
return ;
}
}
} else {
string temp1 = s.substr(0, 3);
string temp2 = s.substr(4, 3);
for (int i = 1; i <= 12; i++) {
if (temp1 == b[i]) {
num += i * 13;
}
if (temp2 == a[i]) {
num += i;
}
}
cout << num;
}
return ;
}

int main() {
int n;
cin >> n;
getchar();
for (int i = 0; i < n; i++) {
string s;
getline(cin, s);
if(isdigit(s[0])) {
func1(s);
} else {
func2(s);
}
cout << endl;
}
return 0;
}