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leetcode Generalized Abbreviation

2016-07-20 19:32 337 查看
Write a function to generate the generalized abbreviations of a word.

Example:

Given word = 
"word"
, return the following list (order does not matter):

["word", "1ord", "w1rd", "wo1d", "wor1", "2rd", "w2d", "wo2", "1o1d", "1or1", "w1r1", "1o2", "2r1", "3d", "w3", "4"]


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主要说一下递归思路,自己之前写的感觉不是很正确,网上看到比较正确的思路是这样的,用一个变量count来表示当前连续的缩写个数,那么当遇到一个新的char时,只有两种选择:1、继续缩写,count+1 2、不缩写,输出当前count,输出该字符,重置count为0,代码:

public List<String> generateAbbreviations(String word) {
List<String> list=new ArrayList<>();
search(word.toCharArray(),list,new StringBuffer(),0,0);

return list;
}
public void search(char[] word,List<String> list,StringBuffer str,int count,int len){
int length=str.length();
if(len==word.length){
if(count!=0)
str.append(count);
list.add(str.toString());
}else{
search(word,list,str,count+1,len+1);
if(count!=0){
str.append(count);
}
search(word,list,str.append(word[len]),0,len+1);
}
str.setLength(length);
}
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标签:  leetcode 算法