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简易的C/S系统(实现两个数的和)

2016-07-15 19:59 399 查看
//Client:
#include <string.h>
#include <sys/socket.h>
#include <stdio.h>
#include <netinet/in.h>

int main(int argc, char **argv){
int sockfd;
struct sockaddr_in address;
int result;
int num1 = 25, num2 = 30, num3 = 0;
printf("请输入两个整数");
scanf("%d%d", &num1, &num2);
sockfd = socket(AF_INET,SOCK_STREAM, 0);
address.sin_family = AF_INET;
address.sin_addr.s_addr = inet_addr("127.0.0.1");
address.sin_port = 6666;
result = connect(sockfd, (struct sockaddr *) &address, sizeof(address));
if(result == -1){
perror("连接失败了");
return 1;
}
write(sockfd, &num1, sizeof(num1));
write(sockfd, &num2, sizeof(num2));
read(sockfd, &num3, sizeof(num3));
printf("两个数的和是%d\n", num3);
close(sockfd);
return 0;
}


//Server
include<stdio.h>
#include<string.h>
#include<sys/socket.h>
#include<netinet/in.h>

int main(int argc, int **argv){
int server_sockfd, client_sockfd;
struct sockaddr_in server_address;
struct sockaddr_in client_address;
//struct sockaddr_in *client_address2;
server_sockfd = socket(AF_INET, SOCK_STREAM, 0);
server_address.sin_family = AF_INET;
server_address.sin_addr.s_addr = inet_addr("127.0.0.1");
server_address.sin_port = 6666;
bind(server_sockfd, (struct sockaddr *) &server_address, sizeof(server_address));
listen(server_sockfd, 10);
int client_len;
//char client_ip[100], client_port[100];
while(1){
int num1, num2, num3;
printf("服务器等待消息\n");
client_len = sizeof(client_address);
client_sockfd = accept(server_sockfd, (struct sockaddr *) &client_address, (socklen_t *__restrict) &client_len);
//sprintf(client_ip, inet_ntoa(client_address.sin_addr));
//client_address2 = (struct sockaddr_in *)&client_address;
//printf("你所连接的主机的ip地址为: %s, 端口号是:\n", inet_ntoa(client_address2->sin_addr));
read(client_sockfd, &num1, sizeof(num1));
printf("第一个数是: %d\n", num1);
read(client_sockfd, &num2, sizeof(num2));
printf("第二个数是: %d\n", num2);
num3 = num1 + num2;
write(client_sockfd, &num3, sizeof(num3));
close(client_sockfd);
}
return 0;
}
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