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C#解析Json字符串

2016-07-12 22:48 429 查看
1.
var resultStr={"from":"en","to":"zh","trans_result":[{"src":"apple","dst":"\u82f9\u679c"}]}
var data = JObject.Parse(resultStr);
if (data.Property("trans_result")!=null)
{
var trans_result = data.Property("trans_result").Value.ToString();
var trans = (JArray) JsonConvert.DeserializeObject(trans_result);
var dst = trans[0]["dst"];
var src = trans[0]["src"];
var fromStr = data.Property("from").Value.ToString();
var tttt = data.Property("to").Value.ToString();
var from = data.Property("from").Value.ToString() == "\"zh\"" ? "中文" : "英文";
var toStr = data.Property("to").Value.ToString() == "\"zh\"" ? "中文" : "英文";
result = string.Format("将{0}从{1}翻译到{2}的意思是:{3},", src.ToString(), from, toStr, dst);
}

2. var obj = JsonConvert.DeserializeObject<JObject>(data);//PuName

var dataStr = obj.Value<string>("data").Replace("\\\"",
"\"").Replace("\\n", " ").Replace("\\t", " ").Replace("\\", "
").Replace("\" \"", "\"").Replace("\"\"黄", "\"黄").Replace("\" \"",
"\"");
var jsonObj = JsonConvert.DeserializeObject<JObject>(dataStr);
var rowstr = "{" + jsonObj.Property("rows").ToString() + "}";
JObject rowList = JObject.Parse(rowstr);
foreach (var r in rowList["rows"])
{
var dy = JsonConvert.DeserializeObject<JObject>(r.ToString());
var PuName = dy.Value<string>("PuName");
PuName = dy["PuName"].ToString();
PuName = dy.Property("PuName").Value.ToString();
}
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