解决SQLSEVER 存储过程入参不能带入in的参数传带逗号值的办法

ALTER PROCEDURE [dbo].[P_UpdateUserLeftRightV2]
@UserId   varchar(50),
@TotalBonus decimal(18,2),
@LeftUsers  varchar(MAX),
@RightUsers varchar(MAX)
AS
BEGIN
SET NOCOUNT ON;
begin tran
begin
if @LeftUsers <> ''
begin
update [User] set LeftTotal=LeftTotal+@TotalBonus,LeftNew=LeftNew+1 where UserID in (<span style="font-family: Arial, Helvetica, sans-serif;">@LeftUser</span><span style="font-family: Arial, Helvetica, sans-serif;">);</span>
end
if @LeftUsers <> ''
begin
update [User] set RightTotal=RightTotal+@TotalBonus,RightNew=RightNew+1 where UserID in (@<span style="font-family: Arial, Helvetica, sans-serif;">RightUsers</span><span style="font-family: Arial, Helvetica, sans-serif;">);</span>
end
update [User] set isupdate = 1 where userid=@UserId;
end

if @@ERROR<>0
rollback tran
else
commit tran

SET NOCOUNT OFF;
END

如上代码：入参 LeftUsers和@RightUsers 是一个字符串，类似 11,22,33，调用后不能实现效果，where不能成立

解决这个问题，可以使用函数来处理，把入参数据构成列在函数的表值函数下面，函数如下

create function [dbo].[f_split](@c varchar(2000),@split varchar(2))

returns @t table(col varchar(20))

as

begin

while(charindex(@split,@c)<>0)

begin

insert @t(col) values (substring(@c,1,charindex(@split,@c)-1))

set @c = stuff(@c,1,charindex(@split,@c),'')

end

insert @t(col) values (@c)

return

end

如何调用如下：select col from [dbo].[f_split](@LeftUsers,',')
ALTER PROCEDURE [dbo].[P_UpdateUserLeftRightV2]
@UserId varchar(50),
@TotalBonus decimal(18,2),
@LeftUsers varchar(MAX),
@RightUsers varchar(MAX)
AS
BEGIN
SET NOCOUNT ON;
begin tran
begin
if @LeftUsers <> ''
begin
update [User] set LeftTotal=LeftTotal+@TotalBonus,LeftNew=LeftNew+1 where UserID in (select col from [dbo].[f_split](@LeftUsers,','));
end
if @LeftUsers <> ''
begin
update [User] set RightTotal=RightTotal+@TotalBonus,RightNew=RightNew+1 where UserID in (select col from [dbo].[f_split](@RightUsers,','));
end
update [User] set isupdate = 1 where userid=@UserId;
end

if @@ERROR<>0
rollback tran
else
commit tran

SET NOCOUNT OFF;
END

即可解决。