一句SQL，判断char列的值是否组成回文字符串

Table t has 2 columns:

id INT;

value CHAR(1);

Column id starts from 0, increased by 1 each row

Column value is a single character string

Table t has at least 1 row

String s is a palindrome when:

s[i] = s[s.length - i - 1] for i = 0 … (s.length – 1) / 2

E.g.: a, aba, abba.

Q: Write one SQL statement to check if the string composed of value of t ordered by id is a palindrome (case sensitive).

Output “Y” or “N”.

with tmp as
(
(select (select count(1) from t1)-1-id as id,value from t1)
except
(select id,value from t1)
)
select
case when count(1)=0
then 'Y' else 'N' end
from tmp;