LeetCode ——258.Add Digits

Given a non-negative integer 

num

, repeatedly add all its digits until the result has only
one digit.

For example:

Given 

num = 38

, the process is like: 

3
+ 8 = 11

, 

1 + 1 = 2

. Since 

2

 has
only one digit, return it.

C语言解答：

int addDigits(int num) {
int result = num;
while(result >= 10)
{
int temp = 0;
while(result / 10 != 0)
{
temp = temp + result % 10;
result = result / 10;
}
result = result + temp;
}
return result;
}