百度地图坐标转换
2016-06-28 10:41
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坐标转换须知:
WGS坐标系是国际通用的一种地心坐标系,WGS本身也有多个版本,具体请见“WGS百科”GCJ-02是国内官方采用的一种坐标系,也叫做火星坐标系,国内坐标系也是基于GCJ-02变种而来的,比如百度坐标系BD-09。
转换代码
static double pi = 3.14159265358979324;//圆周率 static double a = 6378245.0;//卫星椭球坐标投影到平面地图坐标系的投影因子 static double ee = 0.00669342162296594323;//椭球的偏心率 public final static double x_pi = 3.14159265358979324 * 3000.0 / 180.0;// 圆周率转换量 /** * WGS转换成百度坐标 */ public static double[] wgs2bd(double lat, double lon) { double[] wgs2gcj = wgs2gcj(lat, lon); double[] gcj2bd = gcj2bd(wgs2gcj[0], wgs2gcj[1]); return gcj2bd; } /** * GCJ转百度坐标 */ public static double[] gcj2bd(double lat, double lon) { double x = lon, y = lat; double z = Math.sqrt(x * x + y * y) + 0.00002 * Math.sin(y * x_pi); double theta = Math.atan2(y, x) + 0.000003 * Math.cos(x * x_pi); double bd_lon = z * Math.cos(theta) + 0.0065; double bd_lat = z * Math.sin(theta) + 0.006; return new double[] { bd_lat, bd_lon }; } /** * 百度坐标转GCJ */ public static double[] bd2gcj(double lat, double lon) { double x = lon - 0.0065, y = lat - 0.006; double z = Math.sqrt(x * x + y * y) - 0.00002 * Math.sin(y * x_pi); double theta = Math.atan2(y, x) - 0.000003 * Math.cos(x * x_pi); double gg_lon = z * Math.cos(theta); double gg_lat = z * Math.sin(theta); return new double[] { gg_lat, gg_lon }; } /** * WGS转GCJ */ public static double[] wgs2gcj(double lat, double lon) { double dLat = transformLat(lon - 105.0, lat - 35.0); double dLon = transformLon(lon - 105.0, lat - 35.0); double radLat = lat / 180.0 * pi; double magic = Math.sin(radLat); magic = 1 - ee * magic * magic; double sqrtMagic = Math.sqrt(magic); dLat = (dLat * 180.0) / ((a * (1 - ee)) / (magic * sqrtMagic) * pi); dLon = (dLon * 180.0) / (a / sqrtMagic * Math.cos(radLat) * pi); double mgLat = lat + dLat; double mgLon = lon + dLon; double[] loc = { mgLat, mgLon }; return loc; } /** * 纬度转换 */ private static double transformLat(double lat, double lon) { double ret = -100.0 + 2.0 * lat + 3.0 * lon + 0.2 * lon * lon + 0.1 * lat * lon + 0.2 * Math.sqrt(Math.abs(lat)); ret += (20.0 * Math.sin(6.0 * lat * pi) + 20.0 * Math.sin(2.0 * lat * pi)) * 2.0 / 3.0; ret += (20.0 * Math.sin(lon * pi) + 40.0 * Math.sin(lon / 3.0 * pi)) * 2.0 / 3.0; ret += (160.0 * Math.sin(lon / 12.0 * pi) + 320 * Math.sin(lon * pi / 30.0)) * 2.0 / 3.0; return ret; } /** * 经度转换 */ private static double transformLon(double lat, double lon) { double ret = 300.0 + lat + 2.0 * lon + 0.1 * lat * lat + 0.1 * lat * lon + 0.1 * Math.sqrt(Math.abs(lat)); ret += (20.0 * Math.sin(6.0 * lat * pi) + 20.0 * Math.sin(2.0 * lat * pi)) * 2.0 / 3.0; ret += (20.0 * Math.sin(lat * pi) + 40.0 * Math.sin(lat / 3.0 * pi)) * 2.0 / 3.0; ret += (150.0 * Math.sin(lat / 12.0 * pi) + 300.0 * Math.sin(lat / 30.0 * pi)) * 2.0 / 3.0; return ret; }
原文转载自http://bbs.lbsyun.baidu.com/forum.php?mod=viewthread&tid=10923
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