leetcode #125 in cpp
2016-06-20 05:01
274 查看
Given a string, determine if it is a palindrome, considering only alphanumeric characters and ignoring cases.
For example,
Note:
Have you consider that the string might be empty? This is a good question to ask during an interview.
For the purpose of this problem, we define empty string as valid palindrome.
Code:
class Solution {
public:
bool isPalindrome(string s) {
int i = 0;
int j = s.length()-1;
while(i<=j){
while( i<s.length() && !isalnum(s[i])){
i++;
}
while(j>=0 && !isalnum(s[j])){
j--;
}
if(i <= j){
if(tolower(s[i]) == tolower(s[j])){
i++;
j--;
}else{
return false;
}
}
}
return true;
}
};
For example,
"A man, a plan, a canal: Panama"is a palindrome.
"race a car"is not a palindrome.
Note:
Have you consider that the string might be empty? This is a good question to ask during an interview.
For the purpose of this problem, we define empty string as valid palindrome.
Code:
class Solution {
public:
bool isPalindrome(string s) {
int i = 0;
int j = s.length()-1;
while(i<=j){
while( i<s.length() && !isalnum(s[i])){
i++;
}
while(j>=0 && !isalnum(s[j])){
j--;
}
if(i <= j){
if(tolower(s[i]) == tolower(s[j])){
i++;
j--;
}else{
return false;
}
}
}
return true;
}
};
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