java实现浮点数转换成人民币读法字符串

package crazyit;

public class Num2Rmb {

private String[] hanArr = {"零", "壹", "贰", "叁", "肆", "伍", "陆", "柒", "捌", "玖"};
private String[] danArr = {"十", "百", "千", "万"};
//    //此方法【数组】仅作参考
//    private String[] div(double num){
//
//        long zheng = (long)num;
//        long part = Math.round((num-zheng)*100);
//        return new String[]{zheng + " ", String.valueOf(part)};
//
//    }

//读取传进的参数
private String maString(double mnumString) {
//将mnumString 强制类型转化为long，取整数部分
long mnumint = (long)mnumString;
long part = Math.round((mnumString - mnumint) * 100);
String result = "";
String result1 = "";
String test = "";
long temp2 ;
int count = 0;

//调用小数方法
result1 = partString(part);

// 主要思想：利用循环导出后四位
do {
count++;
temp2 = mnumint % 10000;

test = String.valueOf(temp2);
if (mnumint == 0) {
continue;
}

switch (count) {
case 1:
result = fourString(test) + result;
break;
case 2:
//对万到千万是否全部为0情况的判断
if (fourString(test)=="") {
result = fourString(test) + result;

}
else {
result = fourString(test) +"万" + result;
}
break;
case 3:

result = fourString(test) +"亿" + result;
default:
break;
}
mnumint = mnumint / 10000;
} while (mnumint != 0);

if (part == 0) {
return result + "圆整";
} else {
return result + "圆" + result1;
}

}

//封装一个每四位一读的方法
private String fourString(String numStr){

String result = "";
int numLen = numStr.length();

for(int i = 0; i < numLen ; i++)
{
int num = numStr.charAt(i) - 48;
if (i !=numLen -1 && num != 0)
{

result += hanArr[num] + danArr[numLen - 2 -i];

}
else
{
if (num == 0)
{
//如果是在首位或末位为0则不读
if (i == numLen-1 || i == 0)
continue;
else if ((numStr.charAt(i+1) - 48) == 0){//如果连续两位是0不读
continue;
}
}
result += hanArr[num];
}

}
return result;
}

//封装一个小数的读法
private String partString(long num) {
String result = "";
int test;
test = (int) (num / 10);
result = hanArr[test] + "角";
result += hanArr[(int)(num % 10)] + "分";
return result;
}
public static void main(String[] args) {
// TODO Auto-generated method stub
Num2Rmb nRmb = new Num2Rmb();
//		System.out.println(Arrays.toString(nRmb.div(2342.342)));
System.out.println(nRmb.maString(100000001));
}

}