java程序---将一个浮点数转换成人民币读法

代码如下：

<span style="font-size:18px;">package test;

import java.util.Scanner;

//将输入的浮点型钱数，转成人民币读法
public class Num2Rmb {

private static double num;
private long zheng,xiao;
private String[] hanArr={"零","壹","贰","叁","肆","伍","陆","柒","捌","玖"};
private String[] danwei={"千","百","十",""};
private String[] jinwei={"","万","亿"};
private int[][] temp= new int[4][18];

//将输入的钱数，转成小数和整数部分
private void swp(){

zheng=(long)num;
xiao=Math.round((num-zheng)*100);
}

//将整数部分按四位划分成3个部分，不存在的补0
private void divide(){

int i,j,k=0;
for(i=0;i<3;i++){

long t1=zheng%10000;
int t=(int) t1;
zheng=zheng/10000;
for(j=3;j>=0;j--){
temp[i][j]=t%10;
t=t/10;
}
}
}

//检测是否要对当前的四位进行处理
private int check(int i){

for(int j=0;j<4;j++)
if(temp[i][j]!=0)
return 1;
return 0;
}

//打印结果
private void print(){

//先处理整数部分
//flag用于表示当前部分是否要处理前导0
int i,j,k,flag=0,cnt=0,flag2=0;
for(i=2;i>=0;i--){
if(check(i)==0){
if(flag==1&&cnt==0){
System.out.print("零");
cnt++;
}
flag=0;
continue;
}
//处理前导0
for(j=0;j<4;j++)
if(temp[i][j]!=0)
break;
flag2=1;
if(j!=0&&flag==1)
System.out.print("零");
int d;
//将末尾的0去掉
for(d=3;d>=0;d--)
if(temp[i][d]!=0)
break;
for(k=j;k<=d;k++){
if(temp[i][k]!=0)
System.out.print(hanArr[temp[i][k]]+danwei[k]);
else if(k-1>=0&&temp[i][k-1]!=0){
System.out.print(hanArr[0]);
}
}
flag=1;
System.out.print(jinwei[i]);
}
if(flag2==1)
System.out.print("元");
//处理小数部分
if(xiao/10!=0)
System.out.print(hanArr[(int)xiao/10]+"角");
if(xiao%10!=0)
System.out.print(hanArr[(int)xiao%10]+"分");
System.out.println();

}

//对外的运行接口
public void run(){

swp();
divide();
print();
}

public static void main(String[] args){

Scanner sc= new Scanner(System.in);
System.out.println("请输入钱数:");
while(sc.hasNext()){

num = sc.nextDouble();
Num2Rmb nr =new Num2Rmb();
/*
//调试部分
nr.swp();
System.out.println(nr.zheng+" "+nr.xiao);
nr.divide();
for(int i=2;i>=0;i--){

for(int j=0;j<4;j++)
System.out.print(nr.temp[i][j]);
System.out.println();
}
nr.print();
*/
nr.run();
System.out.println("请输入钱数:");
}
}
}
</span>