mysql 查询表注释/字段注释
2016-06-15 16:17
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Select table_name 表名,TABLE_COMMENT 表注释 from INFORMATION_SCHEMA.TABLES Where table_schema = 'mstps' ##数据库名
AND table_name LIKE 'ms_staff';##表名
Select COLUMN_NAME 列名, COLUMN_TYPE 字段类型, COLUMN_COMMENT 字段注释
from INFORMATION_SCHEMA.COLUMNS
Where table_name = 'ms_staff'##表名
AND table_schema = 'mstps';##数据库名
##AND column_name LIKE 'c_name'##字段名
SELECT COLUMN_NAME as '列名',COLUMN_COMMENT,DATA_TYPE as '字段类型' ,COLUMN_TYPE as '长度加类型' FROM information_schema.`COLUMNS` where TABLE_NAME like 'ms_staff';
select a.table_name , a.table_comment from (SELECT * FROM INFORMATION_SCHEMA.TABLES Where table_schema = 'mstps') a WHERE (a.TABLE_COMMENT) IN(
Select b.TABLE_COMMENT FROM (SELECT * FROM INFORMATION_SCHEMA.TABLES Where table_schema = 'mstps') b GROUP BY (b.TABLE_COMMENT)
HAVING COUNT(*)>1
); ##查询单个数据库所有重复的数据
Select a.table_name dBname,a.TABLE_COMMENT sheetNotes from INFORMATION_SCHEMA.TABLES a Where table_schema = 'mstps' and a.TABLE_COMMENT LIKE CONCAT('%','购物车','%');##查询重复数据为'xx'的行
select * from xi a where (a.username) in (select username from xi group by username having count(*) > 1); ##查询重复数据
AND table_name LIKE 'ms_staff';##表名
Select COLUMN_NAME 列名, COLUMN_TYPE 字段类型, COLUMN_COMMENT 字段注释
from INFORMATION_SCHEMA.COLUMNS
Where table_name = 'ms_staff'##表名
AND table_schema = 'mstps';##数据库名
##AND column_name LIKE 'c_name'##字段名
SELECT COLUMN_NAME as '列名',COLUMN_COMMENT,DATA_TYPE as '字段类型' ,COLUMN_TYPE as '长度加类型' FROM information_schema.`COLUMNS` where TABLE_NAME like 'ms_staff';
select a.table_name , a.table_comment from (SELECT * FROM INFORMATION_SCHEMA.TABLES Where table_schema = 'mstps') a WHERE (a.TABLE_COMMENT) IN(
Select b.TABLE_COMMENT FROM (SELECT * FROM INFORMATION_SCHEMA.TABLES Where table_schema = 'mstps') b GROUP BY (b.TABLE_COMMENT)
HAVING COUNT(*)>1
); ##查询单个数据库所有重复的数据
Select a.table_name dBname,a.TABLE_COMMENT sheetNotes from INFORMATION_SCHEMA.TABLES a Where table_schema = 'mstps' and a.TABLE_COMMENT LIKE CONCAT('%','购物车','%');##查询重复数据为'xx'的行
select * from xi a where (a.username) in (select username from xi group by username having count(*) > 1); ##查询重复数据
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