C/C++斐波那契数列

//输出前n个斐波那契数
#include<iostream>
using namespace std;
int main(void)
{
int fib (int);
int n;
cout<<"Please int put a number:";
cin>>n;
cout<<fib(n)<<endl;
return 0;
}
int fib (int x)
{

int f1=1,f2=2,f3;
if (x>2)
cout<<"1 ";

x=x-2;
while (x--)
{
f3=f1+f2;
f1=f2;
f2=f3;
cout<<f1<<" ";
}

return f3;
}