二维数组m*n的鞍点
2016-06-02 18:21
134 查看
Option Base 1
Dim anma() As Integer
Dim m As Byte, n As Byte
Private Sub Command1_Click()
Cls
Me.Font.Size = 30
m = 5: n = 6
ReDim anma(m, n)
Dim i As Byte, j As Byte
For i = 1 To m
For j = 1 To n
anma(i, j) = 10 + Int(Rnd * 90)
Next j
Print
Next i
For i = 1 To m
For j = 1 To n
Print anma(i, j); Space(3);
Next j
Print
Next i
Dim row_max As Integer, column_max As Byte
Dim k As Byte
For i = 1 To m
row_max = anma(i, 1)
column_max = 1
For j = 2 To n
If anma(i, j) > row_max Then
row_max = anma(i, j)
column_max = j
End If
Next j
For k = 1 To m
If anma(k, column_max) < row_max Then
Exit For
End If
Next k
If k = m + 1 Then
Print "鞍点:" & i & "," & column_max
End If
Next i
End Sub
实验心得
如果k<m,无鞍点;k>m+1,有鞍点
Dim anma() As Integer
Dim m As Byte, n As Byte
Private Sub Command1_Click()
Cls
Me.Font.Size = 30
m = 5: n = 6
ReDim anma(m, n)
Dim i As Byte, j As Byte
For i = 1 To m
For j = 1 To n
anma(i, j) = 10 + Int(Rnd * 90)
Next j
Next i
For i = 1 To m
For j = 1 To n
Print anma(i, j); Space(3);
Next j
Next i
Dim row_max As Integer, column_max As Byte
Dim k As Byte
For i = 1 To m
row_max = anma(i, 1)
column_max = 1
For j = 2 To n
If anma(i, j) > row_max Then
row_max = anma(i, j)
column_max = j
End If
Next j
For k = 1 To m
If anma(k, column_max) < row_max Then
Exit For
End If
Next k
If k = m + 1 Then
Print "鞍点:" & i & "," & column_max
End If
Next i
End Sub
实验心得
如果k<m,无鞍点;k>m+1,有鞍点
相关文章推荐
- 如何简单有效的删除win10英语美式键盘
- ClassLoader的一个应用场景
- Android studio常用快捷键
- QT窗口置顶/真透明/背景模糊/非矩形/跳过任务栏分页器/无边框/无焦点点击/焦点穿透
- chisel(安装)
- 高德地图在个别机型手机上运行崩溃的问题
- easyui 设置无效 jquery-easyui-1.3.6
- Windows下更改MySQL数据库的存储位置
- codeforces 115A
- #18 – Silverlight and WPF Differences(Silverlight和WPF的区别)
- Windows下更改MySQL数据库的存储位置
- 冲刺3
- Jmeter 之集合点
- Linux proc文件系统杂记
- 多线程的简单使用
- 获得android 应用的版本和当前android系统版本
- lnmp重置mysql密码
- vs2013安装及测试
- 前端知识的一些总结
- 桶排序——java