USACO : name that number

#include <iostream>
#include <cstring>
#include <cstdio>
#include <fstream>

using namespace std;

char d[5000][20];
char m[26] = {'2','2','2','3','3','3','4','4','4','5','5','5','6','6','6','7','0','7','7','8','8','8','9','9','9','0'};
char num[20];

int main()
{
ifstream fin;
fin.open("dict.txt");
ifstream in;
in.open("namenum.in");
ofstream fout;
fout.open("namenum.out");
int count = 0;
while(fin >> d[count]){
count++;
}
in >> num;
int flag = 0;

for(int i = 0; i < count; i++){
int FLAG = 0;
if(strlen(d[i]) != strlen(num)) continue;
for(int j = 0; j < strlen(d[i]); j++){
if((m[d[i][j] - 'A'] == num[j] )) continue;
else{                    //字符的ascii码转成数值来比较
FLAG = 1;
break;
}

}
if(!FLAG){
flag = 1;
fout << d[i] <<endl;
}
}
if(!flag) fout<<"NONE"<<endl;
return 0;
}