hdoj2052Picture

[align=left]Problem Description[/align]
Give you the width and height of the rectangle,darw it.

[align=left]Input[/align]
Input contains a number of test cases.For each case ,there are two numbers n and m (0 < n,m < 75)indicate the width and height of the rectangle.Iuput ends of EOF.

[align=left]Output[/align]
For each case,you should draw a rectangle with the width and height giving in the input.

after each case, you should a blank line.

[align=left]Sample Input[/align]

3 2

[align=left]Sample Output[/align]

+---+
|   |
|   |
+---+

题意：给出矩形的场合宽，输出一个矩形，如示例所示，四个角是+。然后用for循环就可以了
代码如下：

#include<stdio.h>
int main()
{
int n,m;
while(scanf("%d%d",&n,&m)!=EOF)
{
int i,j;
for(i=1;i<=m+2;i++)
{
for(j=1;j<=n+2;j++)
{
if((i==1||i==m+2)&&(j==1||j==n+2))
{
printf("+");
}
else if(i==1||i==m+2)
{
printf("-");
}
else if((i!=1&&i!=m+2)&&(j==1||j==n+2))
{
printf("|");
}
else
printf(" ");
if(j==n+2)
{
printf("\n");
}
}
if(i==m+2)
printf("\n");
}

}
}