python实现欧拉计划24题

逆康拓展开式

import math

L=[0,1,2,3,4,5,6,7,8,9]

M=[]

m=999999

for i in range(9,-1,-1):

    x=(m/(math.factorial(i)))

    print x

    y=(m%(math.factorial(i)))

    m=y

    M.append(L[x])

    L.pop(x)

    print L
print M

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使用Python的工具更方便啊啊啊，好神奇的python

import itertools

print([x for x in itertools.islice(itertools.permutations([0,1,2,3,4,5,6,7,8,9],10),999999,1000000)])