1104. Sum of Number Segments (20)【数学题】——PAT (Advanced Level) Practise
2016-05-14 20:49
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题目信息
1104. Sum of Number Segments (20)时间限制200 ms
内存限制65536 kB
代码长度限制16000 B
Given a sequence of positive numbers, a segment is defined to be a consecutive subsequence. For example, given the sequence {0.1, 0.2, 0.3, 0.4}, we have 10 segments: (0.1) (0.1, 0.2) (0.1, 0.2, 0.3) (0.1, 0.2, 0.3, 0.4) (0.2) (0.2, 0.3) (0.2, 0.3, 0.4) (0.3) (0.3, 0.4) (0.4).
Now given a sequence, you are supposed to find the sum of all the numbers in all the segments. For the previous example, the sum of all the 10 segments is 0.1 + 0.3 + 0.6 + 1.0 + 0.2 + 0.5 + 0.9 + 0.3 + 0.7 + 0.4 = 5.0.
Input Specification:
Each input file contains one test case. For each case, the first line gives a positive integer N, the size of the sequence which is no more than 10^5. The next line contains N positive numbers in the sequence, each no more than 1.0, separated by a space.
Output Specification:
For each test case, print in one line the sum of all the numbers in all the segments, accurate up to 2 decimal places.
Sample Input:
4
0.1 0.2 0.3 0.4
Sample Output:
5.00
解题思路
直接看代码吧,,不想多说,AC代码
#include <cstdio> int main() { int n; long long st = 0; double s = 0, v; scanf("%d", &n); for (int i = 0; i < n; ++i){ scanf("%lf", &v); st += n - i - i; s += v * st; } printf("%.2f\n", s); return 0; }
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