Mysql 实现 Rownum() 排序后根据条件获取名次

初始化表结构

DROP TABLE IF EXISTS `data`;
CREATE TABLE `data` (
`dates` varchar(255) CHARACTER SET utf8 DEFAULT NULL,
`id` int(11) DEFAULT NULL,
`result` varchar(255) CHARACTER SET utf8 DEFAULT NULL
);
INSERT INTO `data` (`dates`, `id`, `result`) VALUES ('2015109101', 1, '胜');
INSERT INTO `data` (`dates`, `id`, `result`) VALUES ('2015110101', 2, '负');
INSERT INTO `data` (`dates`, `id`, `result`) VALUES ('2015109101', 3, '负');
INSERT INTO `data` (`dates`, `id`, `result`) VALUES ('2015109101', 4, '胜');
INSERT INTO `data` (`dates`, `id`, `result`) VALUES ('2015110101', 5, '胜');
INSERT INTO `data` (`dates`, `id`, `result`) VALUES ('2015109101', 6, '负');
INSERT INTO `data` (`dates`, `id`, `result`) VALUES ('2015109101', 7, '胜');
INSERT INTO `data` (`dates`, `id`, `result`) VALUES ('2015110101', 8, '负');

排序

select @rownum:=@rownum+1 AS rownum,id,dates
from
`data`,(SELECT @rownum:=0) r
ORDER BY dates;

结果

条件查询

SELECT rownum,id
from
(select @rownum:=@rownum+1 AS rownum,id,dates
from
`data`,(SELECT @rownum:=0) r
ORDER BY dates)b
WHERE id =2;

结果

写在最后的话