LeetCode 57. Insert Interval
2016-05-09 05:13
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#include <iostream> #include <vector> using namespace std; /* Given a set of non-overlapping intervals, insert a new interval into the intervals(merge is necessary) You may assume that the intervals were initially sorted according to their start times. 1> Given intervals [1, 3], [6, 9], insert and merge [2, 5] in as [1, 5], [6, 9]; 2> Given [1,2],[3,5],[6,7],[8,10],[12,16], insert and merge [4,9] in as [1,2],[3,10],[12,16]. This is because the new interval [4,9] overlaps with [3,5],[6,7],[8,10]. */ struct Interval { int start; int end; Interval() : start(0), end(0) {} Interval(int s, int e): start(s), end(e) {} }; vector<Interval> insert(vector<Interval>& intervals, Interval newInterval) { int n = intervals.size(); if(n == 0) return {newInterval}; int i = 0; Interval tmp; vector<Interval> res; while(i < n && newInterval.start > intervals[i].end) { res.push_back(intervals[i]); i++; } while(i < n && newInterval.end >= intervals[i].start) { newInterval.end = max(newInterval.end, intervals[i].end); newInterval.start = min(newInterval.start, intervals[i].start); i++; } res.push_back(newInterval); while(i < n) { res.push_back(intervals[i]); i++; } return res; } void printInterval(vector<Interval> intervals) { for(int i = 0; i < intervals.size(); ++i) { cout << "[" << intervals[i].start << "," << intervals[i].end << "] "; } cout << endl; } int main(void) { vector<Interval> example_1{Interval(1, 3), Interval(6, 9)}; Interval tmp_interval(2, 5); vector<Interval> res = insert(example_1, tmp_interval); printInterval(res); vector<Interval> example_2{Interval(1, 2), Interval(3, 5), Interval(8, 10), Interval(12, 16)}; Interval tmp(4, 9); vector<Interval> res_1 = insert(example_2, tmp); printInterval(res_1); }
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