您的位置:首页 > 产品设计 > UI/UE

LeetCode 63 - Unique Paths II

2016-04-05 17:11 489 查看

Unique Paths II

Follow up for "Unique Paths":

Now consider if some obstacles are added to the grids. How many unique paths would there be?

An obstacle and empty space is marked as 
1
 and 
0
 respectively
in the grid.

For example,

There is one obstacle in the middle of a 3x3 grid as illustrated below.
[
[0,0,0],
[0,1,0],
[0,0,0]
]


The total number of unique paths is 
2
.

Note: m and n will be at most 100.

My Code

class Solution {
public:
int uniquePathsWithObstacles(vector<vector<int>>& obstacleGrid) {
int m = obstacleGrid.size(), n = obstacleGrid[0].size();
vector<vector<int> > grid(m, vector<int>(n, 0));

int ii = 0;
for (; ii < m && obstacleGrid[ii][0] == 0; ii++)
grid[ii][0] = 1;
int jj = 0;
for (; jj < n && obstacleGrid[0][jj] == 0; jj++)
grid[0][jj] = 1;

for (int i = 1; i < m; i++)
for (int j = 1; j < n; j++)
{
if (obstacleGrid[i][j] == 1)
continue;

grid[i][j] = grid[i-1][j] + grid[i][j-1];
}

return grid[m-1][n-1];
}
};
Runtime: 6 ms

内容来自用户分享和网络整理,不保证内容的准确性,如有侵权内容,可联系管理员处理 点击这里给我发消息
标签: