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模拟退火

2016-04-03 17:31 387 查看

模拟退火算法概述

模拟退火算法来源于固体退火原理,将固体加温至充分高,再让其徐徐冷却,加温时,固体内部粒子随温升变为无序状,内能增大,而徐徐冷却时粒子渐趋有序,在每个温度都达到平衡态,最后在常温时达到基态,内能减为最小。根据
Metropolis
准则,粒子在温度T时趋于平衡的概率为
e-ΔE/(kT)
,其中E为温度T时的内能,ΔE为其改变量,k为
Boltzmann
常数。用固体退火模拟组合优化问题,将内能E模拟为目标函数值f,温度T演化成控制参数t,即得到解组合优化问题的模拟退火算法:由初始解i和控制参数初值t开始,对当前解重复“产生新解→计算目标函数差→接受或舍弃”的迭代,并逐步衰减t值,算法终止时的当前解即为所得近似最优解,这是基于蒙特卡罗迭代求解法的一种启发式随机搜索过程。退火过程由冷却进度表(Cooling Schedule)控制,包括控制参数的初值t及其衰减因子Δt、每个t值时的迭代次数L和停止条件S。

流程图



代码实现

伪代码

Simulated-Annealing()
Create initial solution S
repeat
for i=1 to iteration-length do
Generate a random transition from S to Si
If ( C(S) <= C(Si) ) then
S=Si
else if( exp(C(S)-C(Si))/kt > random[0,1) ) then
S=Si
Reduce Temperature t
until ( no change in C(S) )

C(S): Cost or Loss function of Solution S


java实例实现

package space.peihao;

import java.io.BufferedReader;
import java.io.File;
import java.io.FileReader;
import java.io.IOException;
import java.util.Arrays;
import java.util.Random;

/**
* @author Dukie 下午02:22:13 2010
*
*/
public class Anneal {

private  static double[][] city;
private  static int[] currPath;
private  static int[] bestPath;
private  static double shortesDistance;
private  static int numOfCity = 20;
//trace item
private static int iterator = 0;

public void printInfo() {
System.out.println("bestPath: " + Arrays.toString(bestPath));
System.out.println("shortest distance: " + shortesDistance);
System.out.println("iterator times: " + iterator);
}

private void init() throws IOException {
city = new double[numOfCity][numOfCity];
currPath = new int[numOfCity];
bestPath = new int[numOfCity];
shortesDistance = 0;
loadCity();
int lenth = currPath.length;
for (int i = 0; i < lenth; i++) {
currPath[i] = i;
}
}

private void loadCity() throws IOException {
//DistanceMatrix.csv" a file stores the distance info.
File file = new File("E:\\TSP\\DistanceMatrix.csv");
inputGraph(file, city);
}

private void inputGraph(File file, double[][] city) throws IOException {
BufferedReader in = new BufferedReader(new FileReader(file));
String str = "";
int length = 0;
while ((str = in.readLine()) != null) {
str = str.replaceAll(", ", ",");
String[] line = str.split(",");
for (int j = 0; j < numOfCity; j++)
// ten cities
city[length][j] = Double.parseDouble(line[j]);
length++;
}
}

/**
* key function
* @throws IOException
*/
public void anneal() throws IOException {

double temperature = 10000.0D;
double deltaDistance = 0.0D;
double coolingRate = 0.9999;
double absoluteTemperature = 0.00001;

init();

double distance = getToatalDistance(currPath);

int[] nextPath;
Random random = new Random();
while (temperature > absoluteTemperature) {
nextPath = generateNextPath();
deltaDistance = getToatalDistance(nextPath) - distance;

if ((deltaDistance < 0)
|| (distance > 0 &&
Math.exp(-deltaDistance / temperature) > random.nextDouble())) {
currPath = Arrays.copyOf(nextPath, nextPath.length);
distance = deltaDistance + distance;
}

temperature *= coolingRate;
iterator++;
System.out.println("iterator: " + iterator + " path: " + Arrays.toString(currPath));
}
shortesDistance = distance;
System.arraycopy(currPath, 0, bestPath, 0, currPath.length);

}

/**
* calculate total distance
* @param currPath
* @return
*/
private double getToatalDistance(int[] currPath) {
int length = currPath.length;
double totalDistance = 0.0D;
for (int i = 0; i < length - 1; i++) {
totalDistance += city[currPath[i]][currPath[i + 1]];
}
totalDistance += city[currPath[length - 1]][0];

return totalDistance;
}

/**
* swap two elements in the old array to genreate new array
* @return
*/
private int[] generateNextPath() {
int[] nextPath = Arrays.copyOf(currPath, currPath.length);
Random random = new Random();
int length = nextPath.length;
int fistIndex = random.nextInt(length - 1) + 1;
int secIndex = random.nextInt(length - 1) + 1;
while (fistIndex == secIndex) {
secIndex = random.nextInt(length - 1) + 1;
}
int tmp = nextPath[fistIndex];
nextPath[fistIndex] = currPath[secIndex];
nextPath[secIndex] = tmp;

return nextPath;
}

}


上述代码就是为了解决旅行商问题。旅行商按一定的顺序访问N个城市的每个城市,使得每个城市都能被访问且仅能被访问一次,最后回到起点,而使花费的代价最小。本例中从第0个城市开始然后回到原点.

Tips

模拟退火算法与初始值无关,算法求得的解与初始解状态S(是算法迭代的起点)无关;模拟退火算法具有渐近收敛性,已在理论上被证明是一种以概率l 收敛于全局最优解的全局优化算法;模拟退火算法具有并行性。
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