进制转换

模拟短除法：



#include <iostream>

#include <stdio.h>

#include <algorithm>

#define INF 1005

using namespace std;

int main()

{

int n,r;

while(scanf("%d %d",&n,&r)!=EOF&&r) {

char ch[]="0123456789ABCDEF";

char s[INF];

if(n < 0) {

n = -n;

cout << "-";

} //注意负数;

;

int j = 0;

while(n) {

s[j++] = ch[n % r];

n /= r;

}

;

for(int i=j-1; i>=0; i--)

cout << s[i];

cout << endl;

}

return 0;

}