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Linux下的C之2048

2016-03-26 00:05 309 查看
#include <stdio.h>
#include <stdlib.h>
#include <curses.h>
#include <time.h>
#include <unistd.h>
#include <signal.h>

// 4*4方格
int a[4][4] = {0};
// 方格里空格的个数
int empty;
int old_y, old_x;

void draw();
void play();
void init();
void draw_one(int y, int x);
void cnt_value(int *new_y, int *new_x);
int game_over();
int cnt_one(int y, int x);

int main()
{
init();
play();
endwin();

return 0;
}

void init()
{
int x, y;

initscr();
cbreak();
noecho();
curs_set(0);

empty = 15;
srand(time(0));
x = rand() % 4;
y = rand() % 4;
a[y][x] = 2;
draw();
}

void draw()
{
int n, m, x, y;
char c[4] = {'0', '0', '0', '0'};

clear();
for(n = 0; n < 9; n += 2)   //横线
for(m = 0; m < 21; m++) {
move(n, m);
addch('-');
refresh();
}
for(m = 0; m < 22; m += 5)  //竖线
for(n = 1; n < 8; n++) {
move(n, m);
addch('|');
refresh();
}
for(y = 0; y < 4; y++)     //数字
for(x = 0; x < 4; x++) {
draw_one(y, x);
}
}

void draw_one(int y, int x)
{
int i, m, k, j;
char c[4] = {'0', '0', '0', '0'};

i = a[y][x];
m = 0;
do {
j = i % 10;
c[m++] = j + '0';
i = i / 10;
}while(i > 0);
m = 0;
k = (x + 1) * 5 - 1;
while(c[m] != '0') {
move(2*y+1, k);
addch(c[m++]);
k--;
}
}

void play()
{
int x, y, i, new_x, new_y, tmp;
int old_empty, move;
char ch;

while(1) {
move = 0;
old_empty = empty;
//draw();
ch = getch();
switch(ch) {
case 'A':
case 'a':
//从左向右消去相同方块
for(y = 0; y < 4; y++)
for(x = 0; x < 4; ) {
if(a[y][x] == 0) {
x++;
continue;
} else {
for(i = x + 1; i < 4; i++) {
if(a[y][i] == 0) {
continue;
}
else {
if(a[y][x] == a[y][i]) {
a[y][x] += a[y][i];
a[y][i] = 0;
x = i + 1;
empty++;
break;
}
else {
x = i;
break;
}
}
}
x = i;
}
}
//向左移动方块
for(y = 0; y < 4; y++)
for(x = 0; x < 4; x++) {
if(a[y][x] == 0) {
continue;
} else {
for(i = x; (i > 0) && (a[y][i-1] == 0); i--) {
a[y][i-1] = a[y][i];
a[y][i] = 0;
move = 1;
}
}
}
break;
case 'D':
case 'd':
//从右向左消去相同方块
for(y = 0; y < 4; y++)
for(x = 3; x >= 0; ) {
if(a[y][x] == 0) {
x--;
continue;
} else {
for(i = x - 1; i >= 0; i--) {
if(a[y][i] == 0) {
continue;
} else if(a[y][x] == a[y][i]) {
a[y][x] += a[y][i];
a[y][i] = 0;
x = i - 1;
empty++;
break;
} else {
x = i;
break;
}
}
x = i;
}
}
//向右移动方块
for(y = 0; y < 4; y++)
for(x = 3; x >= 0; x--) {
if(a[y][x] == 0) {
continue;
} else {
for(i = x; (i < 3) && (a[y][i+1] == 0); i++) {
a[y][i+1] = a[y][i];
a[y][i] = 0;
move = 1;
}
}
}
break;
case 'W':
case 'w':
//从上向下消去相同方块
for(x = 0; x < 4; x++)
for(y = 0; y < 4; ) {
if(a[y][x] == 0) {
y++;
continue;
} else {
for(i = y + 1; i < 4; i++) {
if(a[i][x] == 0) {
continue;
} else if(a[y][x] == a[i][x]) {
a[y][x] += a[i][x];
a[i][x] = 0;
y = i + 1;
empty++;
break;
} else {
y = i;
break;
}
}
y = i;
}
}
//向上移动方块
for(x = 0; x < 4; x++)
for(y = 0; y < 4; y++) {
if(a[y][x] == 0) {
continue;
} else {
for(i = y; (i > 0) && (a[i-1][x] == 0); i--) {
a[i-1][x] = a[i][x];
a[i][x] = 0;
move = 1;
}
}
}
break;
case 'S':
case 's':
//从下向上消去相同方块
for(x = 0; x < 4; x++)
for(y = 3; y >= 0; ) {
if(a[y][x] == 0) {
y--;
continue;
} else {
for(i = y - 1; i >= 0; i--) {
if(a[i][x] == 0) {
continue;
} else if(a[y][x] == a[i][x]) {
a[y][x] += a[i][x];
a[i][x] = 0;
y = i -1;
empty++;
break;
} else {
y = i;
break;
}
}
y = i;
}
}
//向下移动方块
for(x = 0; x < 4; x++)
for(y = 3; y >= 0; y--) {
if(a[y][x] == 0) {
continue;
} else {
for(i = y; (i < 3) && (a[i+1][x] == 0); i++) {
a[i+1][x] = a[i][x];
a[i][x] = 0;
move = 1;
}
}
}
break;
case 'Q':
case 'q':
game_over();
break;
default:
continue;
break;
}

if(empty <= 0)
game_over();
draw();
//生成新方块
if((empty != old_empty) || (move == 1)) {  //修复了不移动或消除方块也生成新方块的bug
do {
new_x = rand() % 4;
new_y = rand() % 4;
}while(a[new_y][new_x] != 0);

cnt_value(&new_y, &new_x);

do {
tmp = rand() % 4;
}while(tmp == 0 || tmp == 2);
a[new_y][new_x] = tmp + 1;
empty--;

draw_one(new_y, new_x);
}
}
}

int cnt_one(int y, int x)
{
int value = 1;

if(y - 1 > 0)
a[y-1][x] ? 0 : value++;
if(y + 1 < 4)
a[y+1][x] ? 0 : value++;
if(x - 1 >= 0)
a[y][x-1] ? 0 : value++;
if(x + 1 < 4)
a[y][x+1] ? 0 : value++;
if(y - 1 >= 0 && x - 1 >= 0)
a[y-1][x-1] ? 0 : value++;
if(y - 1 >= 0 && x + 1 < 4)
a[y-1][x+1] ? 0 : value++;
if(y + 1 < 4 && x - 1 >= 0)
a[y+1][x-1] ? 0 : value++;
if(y + 1 < 4 && x + 1 < 4)
a[y+1][x+1] ? 0 : value++;

return value;
}

void cnt_value(int *new_y, int *new_x)
{
int max_x, max_y, x, y, value;
int max = 0;

max = cnt_one(*new_y, *new_x);
for(y = 0; y < 4; y++)
for(x = 0; x < 4; x++) {
if(!a[y][x]) {
value = cnt_one(y, x);
if(value > max && old_y != y && old_x != x) {  //避免在同一位置反复出现新方块
*new_y = y;
*new_x = x;
old_x = x;
old_y = y;
break;
}
}
}
}

int game_over()
{
sleep(1);
endwin();
exit(0);
}


vim game_2048.c,按下i进入编辑模式,然后将上面的代码复制进去,再按Esc退出编辑模式,按下:x保存并退出。

然后在终端运行:gcc game_2048.c -o 2048 -lcurses 进行编译,最后输入./2048即可运行2048。方向键是wasd。

效果截图:
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