您的位置:首页 > 产品设计 > UI/UE

[LeetCode]Unique Paths

2016-03-18 15:40 267 查看
题目描述:

A robot is located at the top-left corner of a m x n grid (marked 'Start' in the diagram below).

The robot can only move either down or right at any point in time. The robot is trying to reach the bottom-right corner of the grid (marked 'Finish' in the diagram below).

How many possible unique paths are there?



Above is a 3 x 7 grid. How many possible unique paths are there?

Note: m and n will be at most 100.

解题思路:

组合数学中的例子,向下m - 1步,向右n - 1步,也就是m + n - 2个数中选择m - 1个数的组合数。

class Solution {
public:
int uniquePaths(int m, int n) {
// 递归超时
// if (n == 1 || m == 1) {
//     return 1;
// } else {
//     return uniquePaths(m - 1, n) + uniquePaths(m, n - 1);
// }

// DP
vector<vector<int>> matrix(m, vector<int>(n, 1));
for (int i = 1; i< m; ++i) {
for (int j = 1; j < n; ++j) {
matrix[i][j] = matrix[i - 1][j] + matrix[i][j - 1];
}
}

return matrix[m - 1][n - 1];
}
};
内容来自用户分享和网络整理,不保证内容的准确性,如有侵权内容,可联系管理员处理 点击这里给我发消息
标签: