LeetCode : Reverse Nodes in k-Group [java]

Given a linked list, reverse the nodes of a linked list k at a time and return its modified list.

If the number of nodes is not a multiple of k then left-out nodes in the end should remain as it is.

You may not alter the values in the nodes, only nodes itself may be changed.

Only constant memory is allowed.

For example,

Given this linked list:

1->2->3->4->5

For k = 2, you should return:

2->1->4->3->5

For k = 3, you should return:

3->2->1->4->5

思路：分组逆转，注意组间连接。

/**
* Definition for singly-linked list.
* public class ListNode {
*     int val;
*     ListNode next;
*     ListNode(int x) { val = x; }
* }
*/
public class Solution {
public ListNode reverseKGroup(ListNode head, int k) {
if (k == 1 || head == null || head.next == null)
return head;
ListNode first = head, last = head;
ListNode preHead = new ListNode(-1);
preHead.next = head;
ListNode preGroup = preHead, nextGroup = preHead;
int count = 1;
while (last != null) {
if (count == k) {
nextGroup = last.next;
reverseList(first, last);
preGroup.next = last;
preGroup = first;
first.next = nextGroup;
first = nextGroup;
last = nextGroup;
count = 1;
continue;
}
last = last.next;
count++;
}
return preHead.next;
}

private void reverseList(ListNode head, ListNode tail) {
ListNode pre = new ListNode(-1);
ListNode node = head;
pre.next = head;
while (pre != tail) {
ListNode temp = node.next;
node.next = pre;
pre = node;
node = temp;
}
}
}