C实现两个大数相加

#include <stdio.h>
#include <string.h>
int main()
{
char snum1[1024], snum2[1024], sop1[1024]="0", sop2[1024];
int len, len1, len2, opsign = 0;
printf( "输入两个操作数:\n" );
scanf( "%s\n%s", snum1, snum2 );
len1 = strlen( snum1 );
len2 = strlen( snum2 );
if( len1 >= len2 )
{
strcat( sop1, snum1 );
strcpy( sop2, snum2 );
len = len1 + 1;
}
else
{
strcat( sop1, snum2 );
strcpy( sop2, snum1 );
len = len2 + 1;
}
for( int i = 0; i != len; i++ )
{
int k = sop1[strlen(sop1)-1-i] - '0';
int m;
if( i >= strlen( sop2 ) ) m=0;
else m = sop2[strlen(sop2)-1-i] - '0';
if( opsign ) k++;
int n = k + m;
if( n >= 10 )
{
opsign = 1;
n = n - 10;
}
else
{
opsign = 0;
}
sop1[strlen(sop1)-1-i] = n + '0';
}
char* p=sop1;
if( sop1[0] == '0' ) printf( "两个操作数之和为:%s", ++p );
else  printf( "两个操作数之和为:%s", p );
getchar();
getchar();
return 0;
}