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Linux 下实现进程退出后自动重启

2016-03-03 18:32 501 查看

Linux 下实现进程退出后自动重启

一般方案有2

1.采用脚本,网上很多,但对一些嵌入式系统因资源限制,大部分命令裁剪了,故不可行

2.采用fork,父进程等待子进程退出

一下采用fork 方法实现,对于重启多个进程,

可采用(pid = waitpid( -1, &status, WNOHANG))避免多个进程同时重启导致僵尸进程

#include <unistd.h>
#include <string.h>
#include <stdio.h>
#include <errno.h>
#include <sys/types.h>
#include <sys/wait.h>
#include <stdlib.h>

#include <string>
using namespace std;

static const char* FULL_NAME= "/usr/bin/server";
static const char* PROGRAM = "server";

static void StartProcess(std::string &name, std::string ¶m)
{
int i = 2;
char tmp[200], *argv[32];
const char *delim=" ";
memcpy(tmp, param.c_str(), 200);
argv[0] = ( char * ) name.c_str();
argv[1] = strtok( ( char * ) tmp, delim);
while ( (argv[i++] = strtok(NULL, delim) ));
argv[i] = NULL;

int status = 0;
string cmd = "killall ";
cmd += PROGRAM;

while (true)
{

int r = system(cmd.c_str());
if (r!=0)
{
printf("WatchDog system err=%d:%s\n",errno,strerror(errno));
}
pid_t pid = fork();
if (pid < 0)
{
printf("WatchDog fork err=%d:%s\n",errno,strerror(errno));
sleep(5);
continue;
}
if (pid == 0)
{
printf("[WatchDog] StartProcess %s ok!\n",name.c_str());
execvp(argv[0], argv);
exit( -1);
}
printf("[WatchDog] chirend pid=%d ok!\n",pid);

if (pid>0)
{
pid_t exitPid = wait(&status);
printf("[WatchDog] pid=%d exitPid=%d!\n",pid,exitPid);
sleep(5);
}
}
}

int main(int argc,char** argv)
{
string name = FULL_NAME;
string param;

StartProcess(name,param);

return 0;
}
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标签:  Linux