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lua中的坑

2016-02-27 20:45 417 查看
  在工作中使用lua也有一年了,代码也写了不少,踩过不少坑,这里记录一下。

table.sort

  table.sort是lua自带的排序函数,数据量小时,也还是不错的。不过要注意你传入的compare函数。例如:

local tb = { 9,8,3,777,0,36548,556,0 }

table.sort( tb,function(a,b) return a>=b end )


上面的代码够简单了,但是你运行起来,却是报错了。

Program starting as '"D:\programs\ZeroBraneStudio\bin\lua53.exe" -e "io.stdout:setvbuf('no')" "D:\work_code\lua\Test\Test.lua"'.
Program 'lua53.exe' started in 'D:\work_code\server' (pid: 6572).
D:\programs\ZeroBraneStudio\bin\lua53.exe: D:\work_code\lua\Test\Test.lua:77: invalid order function for sorting
stack traceback:
[C]: in function 'sort'
D:\work_code\lua\Test\Test.lua:77: in main chunk
[C]: in ?
Program completed in 0.04 seconds (pid: 6572).


原因在于compare函数中不能出现等于,即a>b或a<b都OK,但不能是a>=b或a<=b。如果使用了=,当数组中出现两个权重一样的元素时,就会报错。具体原因你可以看table.sort的官方文档,有句话:

If comp is given, then it must be a function that receives two list elements and returns true when the first element must come before the second in the final order (so that, after the sort, i < j implies not comp(list[j],list[i]))


如果是报invalid order function for sorting也就罢了,网上查一下就能找到答案。然而我在项目中的报错却比较奇怪:

function Society_city:do_player_hurt_sort()
local player_hurt = {}
for ty,hurt_info in pairs( self.player_hurt ) do
for pid,info in pairs( hurt_info ) do
local _info = {}
_info.ty = ty
_info.pid = pid
_info.hurt = info.hurt
_info.times = info.times

table.insert( player_hurt,_info )
end
end

table.sort( player_hurt,function(a,b) return a.hurt >= b.hurt end )

return player_hurt
end


报错信息为:

society_city.lua:679: attempt to index local 'a' (a nil value)


我一直以为是数组中加入了一个nil,但查了半天,原来是>=的原因。

table编译

在我们的项目中,策划将配置填到excel表,然后用工具将excel表批量转为lua表作为配置。这样在lua中直接require就可以使用配置了。转出来的配置表通常是这样的:

local t =
{
[1] =
{
['id'] = 1,
['icon'] = 1001,
['name'] = '默认头像框',
['description'] = '初始赠送',
['type_id'] = 1,
['sort'] = 1,
},

[2] =
{
['id'] = 2,
['icon'] = 1002,
['name'] = '10级头像框',
['description'] = '达到$1级即可获得',
['type_id'] = 2,
['num'] = 10,
['sort'] = 2,
},

[3] =
{
['id'] = 3,
['icon'] = 1003,
['name'] = '20级头像框',
['description'] = '达到$1级即可获得',
['type_id'] = 2,
['num'] = 20,
['sort'] = 3,
},

[4] =
{
['id'] = 4,
['icon'] = 1004,
['name'] = '30级头像框',
['description'] = '达到$1级即可获得',
['type_id'] = 2,
['num'] = 30,
['sort'] = 4,
},

[5] =
{
['id'] = 5,
['icon'] = 1005,
['name'] = '40级头像框',
['description'] = '达到$1级即可获得',
['type_id'] = 2,
['num'] = 40,
['sort'] = 5,
},

[6] =
{
['id'] = 6,
['icon'] = 1006,
['name'] = '50级头像框',
['description'] = '达到$1级即可获得',
['type_id'] = 2,
['num'] = 50,
['sort'] = 6,
},

[7] =
{
['id'] = 7,
['icon'] = 1007,
['name'] = '60级头像框',
['description'] = '达到$1级即可获得',
['type_id'] = 2,
['num'] = 60,
['sort'] = 7,
},

}


View Code
在某些功能中,是需要将id从小到大遍历的。由于策划配置时总是严格按小到大的,转换出来的配置表key值也是从小到大的。然而,当我们require这个table时,顺序却是乱的。即

for k,v in pairs( t ) do
print( k,v )
end

输出:

Program 'lua.exe' started in 'D:\work_code\server' (pid: 8044).
2    table: 0x003d8ff8
5    table: 0x003d92c8
3    table: 0x003d90e8
7    table: 0x003d8a58
1    table: 0x003da560
4    table: 0x003d91d8
6    table: 0x003d92f0
Program completed in 0.03 seconds (pid: 8044).


这样的代码,第一个取得的id并不一定是1。也就是说,lua虚拟机在编译这个文件时,里面的元素并不是按顺序的,即使key值是int型并且按从小到大并严格自增。
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