PAT(Basic Level) 1002.写出这个数 (20)

//由于unsigned long long int的长度也最多达到18446744073709551615，不满足题目要求

//故而将输入x变成字符型数组，再用p指针指向该数组，用<span style="font-family: Arial, Helvetica, sans-serif;">(*p-'0')来将字符转化成数字</span>

#include <iostream>using namespace std;int main(int argc, char *argv[]){int i=0,sum=0,temp;char x[100];char *p=x;string num[10]={"ling","yi","er","san","si","wu","liu","qi","ba","jiu"};string s[50]={};cin>>x;while(*p!='\0'){sum=sum + (*p-'0'); //<span style="font-family: Arial, Helvetica, sans-serif;">用</span><span style="font-family: Arial, Helvetica, sans-serif;">(*p-'0')来将字符转化成数字</span>p++;}while(sum!=0){s[i]=num[sum%10];sum=sum/10;i++;}for(i=i-1;i>0;i--){cout<<s[i]<<" ";}cout<<s[0];system("pause");return 0;}