1015. Reversible Primes (20)
2016-02-19 14:17
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A reversible prime in any number system is a prime whose "reverse" in that number system is also a prime. For example in the decimal system 73 is a reversible prime because its reverse 37 is also a prime.
Now given any two positive integers N (< 105) and D (1 < D <= 10), you are supposed to tell if N is a reversible prime with radix D.
Input Specification:
The input file consists of several test cases. Each case occupies a line which contains two integers N and D. The input is finished by a negative N.
Output Specification:
For each test case, print in one line "Yes" if N is a reversible prime with radix D, or "No" if not.
Sample Input:
Sample Output:
#include <iostream>
#include <cstdio>
#include <cmath>
using namespace std;
bool isPrime(int n){
if(n <= 1) return false;
int nn = sqrt(n);
for(int i = 2; i <= nn; ++i){
if(n % i == 0) return false;
}
return true;
}
int reverse(int n, int radix){
int sum = 0;
do{
sum = sum * radix + n % radix;
n /= radix;
}while(n);
return sum;
}
int main(){
int n, d;
while(true){
scanf("%d", &n);
if(n < 0) break;
scanf("%d", &d);
if(isPrime(n) && isPrime(reverse(n, d))) printf("Yes\n");
else printf("No\n");
}
return 0;
}
Now given any two positive integers N (< 105) and D (1 < D <= 10), you are supposed to tell if N is a reversible prime with radix D.
Input Specification:
The input file consists of several test cases. Each case occupies a line which contains two integers N and D. The input is finished by a negative N.
Output Specification:
For each test case, print in one line "Yes" if N is a reversible prime with radix D, or "No" if not.
Sample Input:
73 10 23 2 23 10 -2
Sample Output:
Yes Yes No
#include <iostream>
#include <cstdio>
#include <cmath>
using namespace std;
bool isPrime(int n){
if(n <= 1) return false;
int nn = sqrt(n);
for(int i = 2; i <= nn; ++i){
if(n % i == 0) return false;
}
return true;
}
int reverse(int n, int radix){
int sum = 0;
do{
sum = sum * radix + n % radix;
n /= radix;
}while(n);
return sum;
}
int main(){
int n, d;
while(true){
scanf("%d", &n);
if(n < 0) break;
scanf("%d", &d);
if(isPrime(n) && isPrime(reverse(n, d))) printf("Yes\n");
else printf("No\n");
}
return 0;
}
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