您的位置:首页 > 编程语言 > Python开发

38. Count and Say leetcode python 2016 new season

2016-01-21 13:09 597 查看
The count-and-say sequence is the sequence of integers beginning as follows:
1, 11, 21, 1211, 111221, ...


1
 is read off as 
"one
1"
 or 
11
.
11
 is read off as 
"two
1s"
 or 
21
.
21
 is read off as 
"one
2
, then 
one 1"
 or 
1211
.

Given an integer n, generate the nth sequence.

Note: The sequence of integers will be represented as a string.

class Solution(object):
def countAndSay(self, n):
"""
:type n: int
:rtype: str
"""
if n == 1:
return '1'
else:
prev = self.countAndSay(n - 1)
start = 0
res = ''
while start < len(prev):
count = 0
cur = prev[start]
while start < len(prev) and cur == prev[start]:
start += 1
count += 1
res += str(count) + cur
return res
内容来自用户分享和网络整理,不保证内容的准确性,如有侵权内容,可联系管理员处理 点击这里给我发消息
标签: