【HDU】 2602 Bone Collector
2016-01-20 21:54
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Bone Collector
[b]Time Limit: 2000/1000 MS (Java/Others) Memory Limit: 32768/32768 K (Java/Others)Total Submission(s): 43693 Accepted Submission(s): 18229
[/b]
[align=left]Problem Description[/align]
Many years ago , in Teddy’s hometown there was a man who was called “Bone Collector”. This man like to collect varies of bones , such as dog’s , cow’s , also he went to the grave …
The bone collector had a big bag with a volume of V ,and along his trip of collecting there are a lot of bones , obviously , different bone has different value and different volume, now given the each bone’s value along his trip , can you calculate out the
maximum of the total value the bone collector can get ?
[align=left]Input[/align]
The first line contain a integer T , the number of cases.
Followed by T cases , each case three lines , the first line contain two integer N , V, (N <= 1000 , V <= 1000 )representing the number of bones and the volume of his bag. And the second line contain N integers representing the value of each bone. The third
line contain N integers representing the volume of each bone.
[align=left]Output[/align]
One integer per line representing the maximum of the total value (this number will be less than 231).
[align=left]Sample Input[/align]
1 5 10 1 2 3 4 5 5 4 3 2 1
[align=left]Sample Output[/align]
14
题解:01背包的裸题。
#include <iostream> #include <cstdio> #include <cstdlib> #include <cstring> using namespace std; int n,v,T,c[1005],val[1005],d[1005]; int main() { scanf("%d",&T); while (T--) { memset(d,0,sizeof(d)); scanf("%d%d",&n,&v); for (int i=1;i<=n;i++) scanf("%d",&val[i]); for (int i=1;i<=n;i++) scanf("%d",&c[i]); for (int i=1;i<=n;i++) for (int j=v;j>=c[i];j--) d[j]=max(d[j],d[j-c[i]]+val[i]); printf("%d\n",d[v]); } return 0; }
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