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hysbz 2243 染色(树链剖分)

2016-01-19 13:40 429 查看
题目链接:hysbz 2243 染色

题目大意:略。

解题思路:树链剖分+线段树的区间合并,可是区间合并比較简单,节点仅仅要记录左右端点的颜色就可以。

#include <cstdio>
#include <cstring>
#include <algorithm>

using namespace std;

const int maxn = 1e5 + 5;

int N, M, ne, val[maxn], first[maxn], jump[maxn * 2];
int id, far[maxn], son[maxn], dep[maxn], top[maxn], cnt[maxn], idx[maxn];
struct Edge {
int u, v;
void set (int u, int v) {
this->u = u;
this->v = v;
}
}ed[maxn * 2];

inline void add_Edge(int a, int b) {
ed[ne].set(a, b);
jump[ne] = first[a];
first[a] = ne++;
}

void dfs_fir(int u, int pre, int d) {
far[u] = pre;
dep[u] = d;
son[u] = 0;
cnt[u] = 1;

for (int i = first[u]; i + 1; i = jump[i]) {
int k = ed[i].v;
if (k == pre)
continue;
dfs_fir(k, u, d + 1);
cnt[u] += cnt[k];
if (cnt[son[u]] < cnt[k])
son[u] = k;
}
}

void dfs_sec(int u, int rot) {
top[u] = rot;
idx[u] = id++;

if (son[u])
dfs_sec(son[u], rot);

for (int i = first[u]; i + 1; i = jump[i]) {
int k = ed[i].v;
if (k == far[u] || k == son[u])
continue;
dfs_sec(k, k);
}
}

#define lson(x) ((x)<<1)
#define rson(x) (((x)<<1)|1)
int lc[maxn << 2], rc[maxn << 2], v[maxn << 2];
struct Seg {
int l, r, s;
Seg (int s = 0, int l = 0, int r = 0) {
this->l = l;
this->r = r;
this->s = s;
}
void maintain(int d) {
s = 1;
l = r = d;
}
}nd[maxn << 2];

inline Seg merge(const Seg& L, const Seg& R) {
if (L.s == 0) return R;
if (R.s == 0) return L;
return Seg(L.s + R.s + (L.r == R.l ? -1 : 0), L.l, R.r);
}

inline void pushdown(int u) {
if (v[u] != -1) {
v[lson(u)] = v[rson(u)] = v[u];
nd[lson(u)].maintain(v[u]);
nd[rson(u)].maintain(v[u]);
v[u] = -1;
}
}

inline void pushup(int u) {
nd[u] = merge(nd[lson(u)], nd[rson(u)]);
}

void build (int u, int l, int r) {
lc[u] = l;
rc[u] = r;
v[u] = -1;

if (l == r) {
nd[u].maintain(-1);
return;
}

int mid = (l + r) / 2;
build(lson(u), l, mid);
build(rson(u), mid + 1, r);
pushup(u);
}

void modify (int u, int l, int r, int w) {
if (l <= lc[u] && rc[u] <= r) {
v[u] = w;
nd[u].maintain(w);
return;
}

pushdown(u);
int mid = (lc[u] + rc[u]) / 2;
if (l <= mid)
modify(lson(u), l, r, w);
if (r > mid)
modify(rson(u), l, r, w);
pushup(u);
}

Seg query(int u, int l, int r) {
if (l <= lc[u] && rc[u] <= r)
return nd[u];

pushdown(u);
Seg ret;
int mid = (lc[u] + rc[u]) / 2;
if (l <= mid)
ret = merge(ret, query(lson(u), l, r));
if (r > mid)
ret = merge(ret, query(rson(u), l, r));
pushup(u);
return ret;
}

void init () {
ne = 0;
id = 1;
memset(first, -1, sizeof(first));

for (int i = 1; i <= N; i++)
scanf("%d", &val[i]);

int a, b;
for (int i = 1; i < N; i++) {
scanf("%d%d", &a, &b);
add_Edge(a, b);
add_Edge(b, a);
}
dfs_fir(1, 0, 0);
dfs_sec(1, 1);

build(1, 1, N);
for (int i = 1; i <= N; i++)
modify(1, idx[i], idx[i], val[i]);

/*
for (int i = 1; i <= N; i++) {
Seg ret = query(1, idx[i], idx[i]);
printf("%d ", ret.r);
}
printf("\n");
*/
}

void modify(int a, int b, int w) {
int p = top[a], q = top[b];
while (p != q) {
if (dep[p] < dep[q]) {
swap(p, q);
swap(a, b);
}
modify(1, idx[p], idx[a], w);
a = far[p];
p = top[a];
}
if (dep[a] > dep[b])
swap(a, b);
modify(1, idx[a], idx[b], w);
}

int query(int a, int b) {
int p = top[a], q = top[b];
Seg one, two;
while (p != q) {
if (dep[p] < dep[q]) {
swap(p, q);
swap(a, b);
swap(one, two);
}
one = merge(query(1, idx[p], idx[a]), one);
a = far[p];
p = top[a];
}

if (dep[a] > dep[b]) {
swap(a, b);
swap(one, two);
}

two = merge(query(1, idx[a], idx[b]), two);
int ret = one.s + two.s;
if (one.l == two.l) ret--;
return ret;
}

int main () {

while (scanf("%d%d", &N, &M) == 2) {
init();

int a, b, w;
char op[5];
while (M--) {
scanf("%s%d%d", op, &a, &b);
if (op[0] == 'C') {
scanf("%d", &w);
modify(a, b, w);
} else
printf("%d\n", query(a, b));
}
}
return 0;
}
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