Uva11292--------------(The Dragon of Loowater)勇者斗恶龙 （排序后贪心）

---恢复内容开始---

题目：

Once upon a time, in the Kingdom of Loowater, a minor nuisance turned into a major problem.

The shores of Rellau Creek in central Loowater had always been a prime breeding ground for geese. Due to the lack of predators, the geese population was out of control. The people of Loowater mostly kept clear of the geese. Occasionally, a goose would attack one of the people, and perhaps bite off a finger or two, but in general, the people tolerated the geese as a minor nuisance.

One day, a freak mutation occurred, and one of the geese spawned a multi-headed fire-breathing dragon. When the dragon grew up, he threatened to burn the Kingdom of Loowater to a crisp. Loowater had a major problem. The king was alarmed, and called on his knights to slay the dragon and save the kingdom.

The knights explained: "To slay the dragon, we must chop off all its heads. Each knight can chop off one of the dragon's heads. The heads of the dragon are of different sizes. In order to chop off a head, a knight must be at least as tall as the diameter of the head. The knights' union demands that for chopping off a head, a knight must be paid a wage equal to one gold coin for each centimetre of the knight's height."

Would there be enough knights to defeat the dragon? The king called on his advisors to help him decide how many and which knights to hire. After having lost a lot of money building Mir Park, the king wanted to minimize the expense of slaying the dragon. As one of the advisors, your job was to help the king. You took it very seriously: if you failed, you and the whole kingdom would be burnt to a crisp!

Input

The input contains several test cases. The first line of each test case contains two integers between 1 and 20000 inclusive, indicating the number n of heads that the dragon has, and the number m of knights in the kingdom. The next nlines each contain an integer, and give the diameters of the dragon's heads, in centimetres. The following mlines each contain an integer, and specify the heights of the knights of Loowater, also in centimetres.

The last test case is followed by a line containing:

0 0

Output

For each test case, output a line containing the minimum number of gold coins that the king needs to pay to slay the dragon. If it is not possible for the knights of Loowater to slay the dragon, output the line:

Loowater is doomed!

这种类型的题其实是一种非常基础的问题，我们知道，每一名骑士都有自己的佣金，而佣金越多代表骑士的能力越强，所能斩杀的恶龙的头的直径就越大，所以，我们要尽量保证能力强的骑士斩杀恶龙相对来说比较大的头，而能力一般的骑士斩杀相对直径小一点的头，所以我们需要将恶龙头的直径和骑士的能力由大到小排序，接着作贪心就OK了~！

#include<iostream>
#include<algorithm>
#include<stdio.h>

using namespace std;

#define MAX 20005

int a[MAX];
int b[MAX];

int main(){

int n ,m ;
while(cin>>n>>m){
if(n == 0 && m == 0)
break;
for( int i = 0 ; i < n ; i++ )
cin>>a[i];
for( int j = 0 ; j < m ; j++ )
cin>>b[j];
sort(a,a+n);
sort(b,b+m);
int cur = 0 ;
int cost = 0 ;
for( int i = 0 ; i < m ; i++ ){
if(b[i] >= a[cur] ){
cost += b[i];
cur++;
if(cur == n)
break;
}
}
if(cur < n)
printf("Loowater is doomed!\n");
else
printf("%d\n",cost);
}
return 0;
}