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python 内建函数

2016-01-14 11:13 411 查看
zip(x,y,z)

In [1]: x = [1, 2, 3]

In [2]: y = [4, 5, 6]

In [3]: xyz = zip(x, y, z)

xyz

[(1, 4, 7), (2, 5, 8), (3, 6, 9)]

hash:

In [11]: print hash('abc')

1453079729188098211

coding:utf-8

mylist=[1,2,3,4,5,7,5,7,8,8]

def function(n):

return n*2

def myfilter(n):

if n !=0:

return 1

def is_even(x):

return x and 1 != 0

b=map(lambda x:x*2,mylist)

d = reduce(lambda x, y: x + y, [2, 3, 4, 5, 6], 1)

c=filter(is_even,mylist)

print d
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