android 连按两次退出程序

[java] view
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private long exitTime = 0;

/**

* 捕捉返回事件按钮

*

* 因为此 Activity 继承 TabActivity 用 onKeyDown 无响应，所以改用 dispatchKeyEvent

* 一般的 Activity 用 onKeyDown 就可以了

*/

@Override

public boolean dispatchKeyEvent(KeyEvent event) {

if (event.getKeyCode() == KeyEvent.KEYCODE_BACK) {

if (event.getAction() == KeyEvent.ACTION_DOWN && event.getRepeatCount() == 0) {

this.exitApp();

}

return true;

}

return super.dispatchKeyEvent(event);

}

/**

* 退出程序

*/

private void exitApp() {

// 判断2次点击事件时间

if ((System.currentTimeMillis() - exitTime) > 2000) {

Toast.makeText(MainActivity.this, "再按一次退出程序", Toast.LENGTH_SHORT).show();

exitTime = System.currentTimeMillis();

} else {

finish();

}

}