您的位置:首页 > 其它

CodeForces 148A Insomnia cure

2015-12-14 17:13 405 查看
A. Insomnia cure

time limit per test
2 seconds

memory limit per test
256 megabytes

input
standard input

output
standard output

«One dragon. Two dragon. Three dragon», — the princess was counting. She had trouble falling asleep, and she got bored of counting lambs when she was nine.

However, just counting dragons was boring as well, so she entertained herself at best she could. Tonight she imagined that all dragons were here to steal her, and she was fighting them off. Every
k-th dragon got punched in the face with a frying pan. Every
l-th dragon got his tail shut into the balcony door. Every
m-th dragon got his paws trampled with sharp heels. Finally, she threatened every
n-th dragon to call her mom, and he withdrew in panic.

How many imaginary dragons suffered moral or physical damage tonight, if the princess counted a total of
d dragons?

Input
Input data contains integer numbers k, l, m, n and
d, each number in a separate line (1 ≤ k, l, m, n ≤ 10,
1 ≤ d ≤ 105).

Output
Output the number of damaged dragons.

Sample test(s)

Input
1
2
3
4
12


Output
12


Input
2
3
4
5
24


Output
17


Note
In the first case every first dragon got punched with a frying pan. Some of the dragons suffered from other reasons as well, but the pan alone would be enough.

In the second case dragons 1, 7, 11, 13, 17, 19 and 23 escaped unharmed.

#include<cstdio>
#include<iostream>
using namespace std;

int main(){
int k,l,m,n,d,i,sum;
sum=0;
scanf("%d\n%d\n%d\n%d\n%d",&k,&l,&m,&n,&d);
for(i=1;i<=d;i++){
if(i%k==0){
sum++;
}
else if(i%l==0){
sum++;
}
else if(i%m==0){
sum++;
}
else if(i%n==0){
sum++;
}
}
printf("%d\n",sum);
return 0;
}
内容来自用户分享和网络整理,不保证内容的准确性,如有侵权内容,可联系管理员处理 点击这里给我发消息
标签: