实现Python str.split功能的小函数

s="""    tt qq xbc wzx  ydc  eeff   mm
asdfa sd s s    ssss   ss
sss  sa   aa   aa   q qq
sd              d              """
lis = s.split()
for k in lis:
print k
i=0
tem = ""
for t in s:
if t!=" ":
tem = tem + t
if i+1 < len(s):
if s[i+1]==" ":
print tem
tem=""
else:
print tem
i=i+1

s="s...s.....d......r....e..."
lis = s.split('..')
print lis
i=0
k=0
tem = ""
for t in s:
if t!=".":
tem = tem + t
j = i
if i+1 < len(s):
if s[i+1]==".":
print tem
tem=""
else:
print tem
else:
if i+1 < len(s):
k=i
if s[k+1]!="." and (k-j)%2==0:
print k,j
if s[k+1]!="." and (k-j)%2!=0:
print "Cant not !"
else:
if (k-j+1)%2!=0:
print j,k
print "Can not !"

i=i+1

def my_split (src,sep):
a= src.find("..")
w1=src[:a]
print w1
b=a
i=0
while b<=len (src) and b != -1:
while src[a:a+len(sep)] == sep:
a=a+len(sep)
b=src.find(sep,a)
if b != -1:
print src[a:b]
else :
print src [a:]
a=b
i=i+1
my_split ("wwwww..wwww..wwww..www",".")

def my_split (src,sep):
b= src.find (sep)
e= src.find (sep)
if b== 0:
print "\'\'"
else:
print src [:e]
while e !=-1:
b=src.find (sep,e)
e=src.find(sep,b+len(sep))
if e-b!=len(sep) and e-b!=-1 :
print src [b+len(sep):e]
elif e==-1:
print src[b:]
else:
print "\'\'"

s="aaa...a..a.....a...addd"
my_split(s,'..')