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hdu 5568 sequence2(dp + 大数)

2015-12-03 20:51 633 查看
题目链接:hdu 5568 sequence2

代码

#include <cstdio>
#include <cstring>
#include <algorithm>

using namespace std;
const int maxn = 105;

struct Bign {
int n, s[maxn<<1];

Bign (int t = 0) { init(); s[0] = t; }

void init () { n = 1; memset(s, 0, sizeof(s)); }
void add(const Bign& a) {
int res = 0;
for (int i = 0; i < a.n || i < n; i++) {
if (i < a.n) res += a.s[i];
if (i < n) res += s[i];
s[i] = res % 10;
res /= 10;
}

n = max(a.n, n);
while (res) {
s[n++] = res % 10;
res /= 10;
}
}
}dp[maxn][maxn], ONE(1);

int N, K, A[maxn];

void solve () {
Bign ans(0);

for (int i = 1; i <= N; i++) {
for (int j = 1; j <= K; j++)
dp[i][j].init();
}
for (int i = 1; i <= N; i++) {
dp[i][1].add(ONE);
ans.add(dp[i][K]);
for (int j = i + 1; j <= N; j++) if (A[i] < A[j]) {
for (int k = 2; k <= K; k++) dp[j][k].add(dp[i][k-1]);
}
}

for (int i = ans.n-1; i >= 0; i--) printf("%d", ans.s[i]);
printf("\n");
}

int main () {
while (scanf("%d%d", &N, &K) == 2) {
for (int i = 1; i <= N; i++) scanf("%d", &A[i]);
solve();
}
return 0;
}
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