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【通讯录系统】:实现一个通讯录(可添加、删除、修改、查找、显示、清空、排序)

2015-11-30 21:09 1046 查看
#define _CRT_SECURE_NO_WARNINGS 1

#include<stdio.h>
#include<stdlib.h>
#include<string.h>
#define NAME_MAX 10
#define SEX_MAX 3
#define AGE_MAX 100
#define TEL_MAX 15
#define ADDR_MAX 20
#define PEOPLE_MAX 1000

typedef struct LINK
{
char name[NAME_MAX];
char sex[SEX_MAX];
int age;
char tel[TEL_MAX];
char addr[ADDR_MAX];
}linkman;

typedef struct PEOPLE
{
int num;
linkman count[1000];
}*people;

int search(people cou, char *name)
{
int i = 0;
for (; i < cou->num; i++)
{
if (strcmp(name, (cou->count[i]).name) == 0)
return i;
}
return -1;
}

void add_linkman(people cou)//添加联系人
{
if (cou->num == 1000)
{
printf("该通讯录已满,无法录入信息!\n");
}
printf("please input name>:\n");
scanf("%s", (cou->count[cou->num]).name);
printf("please input the sex>:\n");
scanf("%s", (cou->count[cou->num]).sex);
printf("please input the age>:\n");
scanf("%d", &(cou->count[cou->num]).age);
printf("please input the telephone>:\n");
scanf("%s", (cou->count[cou->num]).tel);
printf("please input the address>:\n");
scanf("%s", (cou->count[cou->num]).addr);
cou->num++;
}

void delete_linkman(people cou)//删除联系人
{
char name[NAME_MAX];
int i = 0;
if (cou->num == 0)
{
printf("该通讯录已空,无法删除信息!\n");
return;
}
printf("请输入要删除人的名字>:");
scanf("%s", &name);
printf("\n");
int ret = search(cou, name);
if (ret == -1)
{
printf("此人不存在,删除失败!\n");
}
else
{
for (i = ret; i < cou->num; i++)
{
cou->count[i] = cou->count[i + 1];
}
cou->num--;
}
}

void find_linkman(people cou)//查找联系人
{
char name[NAME_MAX];
int i = 0;
printf("请输入要查找人的名字>:");
scanf("%s", name);
if (cou->num == 0)
{
printf("当前为空表,查找失败!\n");
return;
}
int ret = search(cou, name);
if (ret != -1)
{
printf("%s\t%s\t%d\t%s\t%s\n",
(cou->count[ret]).name,
(cou->count[ret]).sex,
(cou->count[ret]).age,
(cou->count[ret]).tel,
(cou->count[ret]).addr);
}
else
{
printf("此联系人不存在,查找失败!\n");
}
}

void change_linkman(people cou)//修改指定人信息
{
char name[NAME_MAX];
int i = 0;
printf("请输入要修改人的名字>:");
scanf("%s", name);
if (cou->num == 0)
{
printf("当前为空表,查找失败!\n");
return;
}
int ret = search(cou, name);
if (ret != -1)
{
printf("please input name again>:\n");
scanf("%s", (cou->count[ret]).name);
printf("please input the sex>:\n");
scanf("%s", (cou->count[ret]).sex);
printf("please input the age>:\n");
scanf("%d", &(cou->count[ret]).age);
printf("please input the telephone>:\n");
scanf("%s", (cou->count[ret]).tel);
printf("please input the address>:\n");
scanf("%s", (cou->count[ret]).addr);
}
}

void display_linkman(people cou)//显示所有联系人
{
int i = 0;
if (cou->num == 0)
{
printf("当前为空表,显示失败!\n");
return;
}
for (i = 0; i < cou->num; i++)
{
printf("%s\t%s\t%d\t%s\t%s",
(cou->count[i]).name,
(cou->count[i]).sex,
(cou->count[i]).age,
(cou->count[i]).tel,
(cou->count[i]).addr);
printf("\n");
}
}

void empty_linkman(people cou)//清空所有联系人
{
cou->num = 0;
}
struct stu
{
char name[15];
};
void name_sort(people cou)//按名字顺序排序所有人
{
int i = 0;
int j = 0;
if (cou->num == 0)
{
printf("当前为空表,排序失败!\n");
return;
}
for (i = 0; i < cou->num - 1; i++)
{
for (j = 0; j < cou->num - i - 1; j++)
{
if (strcmp(cou->count[j].name, (cou->count[j + 1]).name)>0)
{
linkman tmp = cou->count[j];
cou->count[j] = cou->count[j + 1];
cou->count[j + 1] = tmp;
}
}

}
}
void menu()
{
printf("************************************\n");
printf("**********1.添加联系人信息**********\n");
printf("********2.删除指定联系人信息********\n");
printf("********3.查找指定联系人信息********\n");
printf("********4.修改指定联系人信息********\n");
printf("********5.显示所有联系人信息********\n");
printf("********6.清空所有联系人************\n");
printf("*******7.以名字排序所有联系人*******\n");
printf("***************0 退出***************\n");
printf("************************************\n");
}

int main()
{
int opp = 1;
struct PEOPLE cou;
cou.num = 0;
while (opp)
{
menu();
printf("请选择>:");
scanf("%d", &opp);
switch (opp)
{
case 0:
exit(EXIT_FAILURE);
break;
case 1:
add_linkman(&cou);
break;
case 2:
delete_linkman(&cou);
break;
case 3:
find_linkman(&cou);
break;
case 4:
change_linkman(&cou);
break;
case 5:
display_linkman(&cou);
break;
case 6:
empty_linkman(&cou);
break;
default:
{
printf("输入有误,请重新输入>:\n");
break;
}
}
}
system("pause");
return 0;
}
如下图(部分截图):






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